Hope this helps :) remember your conversions and just practice it's fairly easy:)
<u>Answer:</u> The element represented by M is Strontium.
<u>Explanation:</u>
Let us consider the molar mass of metal be 'x'.
The molar mass of MO will be = Molar mass of oxygen + Molar mass of metal = (16 + x)g/mol
It is given in the question that 15.44% of oxygen is present in metal oxide. So, the equation becomes:
![\frac{15.44}{100}\times (x+16)=16g/mol\\\\(x+16)=\frac{16g/mol\times 100}{15.44}\\\\x=(103.626-16)g/mol\\\\x=87.62g/mol](https://tex.z-dn.net/?f=%5Cfrac%7B15.44%7D%7B100%7D%5Ctimes%20%28x%2B16%29%3D16g%2Fmol%5C%5C%5C%5C%28x%2B16%29%3D%5Cfrac%7B16g%2Fmol%5Ctimes%20100%7D%7B15.44%7D%5C%5C%5C%5Cx%3D%28103.626-16%29g%2Fmol%5C%5C%5C%5Cx%3D87.62g%2Fmol)
The metal atom having molar mass as 87.62/mol is Strontium.
Hence, the element represented by M is Strontium.
1. Find its coordination figure/coordination number of central atom (CF)
Ev = Vallence electron of central atom
Σe = electrons donated from substituents
Terminal O gives 0 electrons, hence Σe = 3 x 0
charge = charge of the compound
2. Find EP (electron pairs) and LP (lone pairs)
LP = CF - EP
3. Draw the skeleton with octet substituents (top right figure)
4. Find formal charge for each atoms (Qf)
5. Write formal charge near atom in skeleton
6. Enjoy
Answer:
See Explanation Below
Explanation:
A) The rate law can only be on the reactant side and you can only determine it after you get the net ionic equation because of spectators cancelling out. So in this case the rate law is k=[CH3Br]^1 [OH-]^1. The powers are there because the rxn is first order.
B) Since the rxn is first order anything you do to it will be the exact same "counter rxn" per say so since you are decreasing the OH- by 5 the rate will decease by 5
C) The rate will increase by 4 since you are doubling both you have to multiply them both.
3 I don’t know but it may be movement