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2 years ago

Electricity and magnetism

Physics

1 answer:

stellarik [79]2 years ago

6 0

Answer:

Electricity is which is possessed by the flow of electrons.

Magnitism is the process in which the magnet attract the things which consist magnetic substance.

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Which is an example of gaining a static charge by conduction?

lianna [129]

Answer:

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Explanation:

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3 years ago

Betty (mass 40 kg), standing on slippery ice, catches her leaping dog (mass 15 kg) moving horizontally at 3.0 m/s. Show that the

MA_775_DIABLO [31]

Answer:

v = 2.18m/s

Explanation:

In order to calculate the speed of Betty and her dog you take into account the law of momentum conservation. The total momentum before Betty catches her dog must be equal to the total momentum after.

Then you have:

$Mv_{1o}+mv_{2o}=(M+m)v$ (1)

M: mass Betty = 40kg

m: mass of the dog = 15kg

v1o: initial speed of Betty = 3.0m/s

v2o: initial speed of the dog = 0 m/s

v: speed of both Betty and her dog = ?

You solve the equation (1) for v:

$v=\frac{Mv_{1o}+mv_{2o}}{M+m}=\frac{(40kg)(3.0m/s)+(15kg)(0m/s)}{40kg+15kg}\\\\v=2.18m/s$

The speed fo both Betty and her dog is 2.18m/s

7 0

3 years ago

A skier (m=59.0 kg) starts sliding down from the top of a ski jump with negligible friction and takes off horizontally. If h = 3

marissa [1.9K]

Answer:

35.20 m

Explanation:

By the law of conservation of energy we have,

$mg(H-h)=\frac{1}{2}mv^2$

$g(H-h)=\frac{1}{2}v^2$

$\Rightarrow H=\frac{v^2}{2g}+h$

where m= mass of the skier, h= 3.00 m

D= horizontal distance=13.9 m

H= maximum height attained

Also, the horizontal distance covered by the skier is

D=vt

$=v\frac{2g}{h}$

$\Rightarrow v^2=\frac{gD^2}{2h}$

thus, height H in terms of D is given by

$H=\frac{D^2}{2h}+h$

$H=\frac{13.9^2}{2\times3}+3$

H=35.20 m

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3 years ago

Perpetual Endless Relentless Stubborn Immovable Steady Tireless Enduring Never-ending Constant Ever-lasting

klasskru [66]

Eleven truly inspiring adjectives !
You've made my day.

Do you have a question to ask ?

5 0

3 years ago

An experiment to measure the speed of light uses an apparatus similar to Fizeau's. The distance between the light source and the

Marina86 [1]

Answer:

$2.88*10^{8} m/s$

Explanation:

The speed of light is given by

$c=\frac {2d}{t}$ and $t=\frac {\theta}{\omega}$ hence

$c=\omega\frac {2d}{\theta}$

Speed of light is given by

$c=900\times 2\pi(\frac {2\times 10}{\frac {2\pi}{2*800}}})=2.88*10^{8} m/s$

4 0

3 years ago