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3 years ago

A solution with a higher concentration of hydroxide ions (oh-) than hydrogen ions (h+)

1 answer:

5 0

A solution with a higher concentration of hydroxide ions than hydrogen ions is basic solution.

This solution formed by Base dissolved in water and release hydroxide ions.

The PH of the solution is greater than 7

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As5F10 compound name

Veseljchak [2.6K]

Pentaarsenic decafluoride
Penta=5
Arsenic=As
Deca=10
Fluoride=F
Drop the -ine and add -ide

6 0

3 years ago

Can someone please help????nThis is sooooo hard

Rashid [163]

Answer:

See explanation.

Explanation:

I highly suggest you watch OChem Tutor's videos on IUPAC nomenclature because the actual naming would take a lot of time to teach in text-based format. But here is how to name them:

1) I think there are two seperate pictures for number 1. The molecule on the left is 1-pentene and the one on the right is 4-methyl-1-pentene. If the whole thing is one molecule but there is just a bond missing where the red marker numbers are, that molecule would be 9-methyl-1,6-decadiene.

2) 4-methyl-2-pentene

3) 2,4-octadiene

4) 1,5-nonadiene

5) 2,5-dimethyl-3-hexene

6) 3,6-dimethyl-2,4-heptadiene

7) 2,5,5-trimethyl-2-hexene

6 0

2 years ago

Cells that produce antibodies that help destroy the pathogens are called what

SOVA2 [1]

Antibodies are produced by a type of white blood cell called a plasma cell.

8 0

3 years ago

Read 2 more answers

Polyatomic ions such as ammonium ions and nitrate ions are ions that consist of

gregori [183]

More than one atom

- Hope this helps :)

5 0

3 years ago

The pH of 0.10 M solution of an acid is 6. What is the acid dissociation constant of the acid?

svlad2 [7]

Answer: Dissociation constant of the acid is $10^{-11}$ .

Explanation: Assuming the acid to be monoprotic, the reaction follows:

$HA\rightleftharpoons H^++A^-$

pH of the solution = 6

and we know that

$pH=-log([H^+])$

$[H^+]=antilog(-pH)$

$[H^+]=antilog(-6)=10^{-6}M$

As HA ionizes into its ions in 1 : 1 ratio, hence

$[H^+]=[A^-]=10^{-6}M$

As the reaction proceeds, the concentration of acid decreases as it ionizes into its ions, hence the decreases concentration of acid at equilibrium will be:

$[HA]=[HA]-[H^+]$