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Usimov [2.4K]
3 years ago
11

A solution with a higher concentration of hydroxide ions (oh-) than hydrogen ions (h+)

Chemistry
1 answer:
Hoochie [10]3 years ago
5 0
A solution with a higher concentration of hydroxide ions than hydrogen ions is basic solution.

This solution formed by Base dissolved in water and release hydroxide ions.

The PH of the solution is greater than 7
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As5F10 compound name
Veseljchak [2.6K]
Pentaarsenic decafluoride
Penta=5
Arsenic=As
Deca=10
Fluoride=F
Drop the -ine and add -ide
6 0
3 years ago
Can someone please help????nThis is sooooo hard
Rashid [163]

Answer:

See explanation.

Explanation:

I highly suggest you watch OChem Tutor's videos on IUPAC nomenclature because the actual naming would take a lot of time to teach in text-based format. But here is how to name them:

1) I think there are two seperate pictures for number 1. The molecule on the left is 1-pentene and the one on the right is 4-methyl-1-pentene. If the whole thing is one molecule but there is just a bond missing where the red marker numbers are, that molecule would be 9-methyl-1,6-decadiene.

2) 4-methyl-2-pentene

3) 2,4-octadiene

4) 1,5-nonadiene

5) 2,5-dimethyl-3-hexene

6) 3,6-dimethyl-2,4-heptadiene

7) 2,5,5-trimethyl-2-hexene

6 0
2 years ago
Cells that produce antibodies that help destroy the pathogens are called what
SOVA2 [1]
Antibodies are produced by a type of white blood cell called a plasma cell.
8 0
3 years ago
Read 2 more answers
Polyatomic ions such as ammonium ions and nitrate ions are ions that consist of
gregori [183]
More than one atom

- Hope this helps :)
5 0
3 years ago
The pH of 0.10 M solution of an acid is 6. What is the acid dissociation constant of the acid?
svlad2 [7]

Answer: Dissociation constant of the acid is 10^{-11}.

Explanation: Assuming the acid to be monoprotic, the reaction follows:

                         HA\rightleftharpoons H^++A^-

pH of the solution = 6

and we know that

pH=-log([H^+])

[H^+]=antilog(-pH)

[H^+]=antilog(-6)=10^{-6}M

As HA ionizes into its ions in 1 : 1 ratio, hence

[H^+]=[A^-]=10^{-6}M

As the reaction proceeds, the concentration of acid decreases as it ionizes into its ions, hence the decreases concentration of acid at equilibrium will be:

[HA]=[HA]-[H^+]

[HA]=0.1M-10^{-6}M

[HA]=0.09999M

Dissociation Constant of acid, K_a is given as:

K_a=\frac{[A^-][H^+]}{HA}

Putting values of [H^+],[A^-]\text{ and }[HA] in the above equation, we get

K_a=\frac{(10^{-6}M).(10^{-6}M)}{0.09999M}

K_a=1.0001\times 10^{-11}M

Rounding it of to one significant figure, we get

K_a=1.0\times 10^{-11}M\approx 10^{-11}M

6 0
3 years ago
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