Ionic compounds generally occur between metals and non-metals due to their large electronegativity difference. You can simple go down Group 1 and Group 17 of the periodic table.
Examples:
NaCl (Sodium Chloride)
KCl (Potassium Chloride)
RbCl (Rubidium Chloride)
CsCl (Cesium Chloride)
Answer:
Explanation:
Cadmium:(Cd)
Cadmium is transition metal present in group twelve. It is soft metal and properties are similar to the other group members like zinc and mercury. Its atomic number is forty eight and have two valance electrons.
Electronic configuration:
Cd₄₈ = [Kr] 4d¹⁰ 5s²
Vanadium: (V)
It is present in group five. It is malleable and ductile transition metal. Its atomic number is twenty three. Vanadium have five valance electrons.
Electronic configuration:
V₂₃ =[Ar] 3d³ 4s²
Xenon: Xe
Xenon is present in group eighteen. It is noble gas. Its outer most valance shell is complete that's why it is inert. its atomic number is fifty four. Xenon have eight valance electrons.
Electronic configuration:
Xe₅₄ = [Kr] 4d¹⁰ 5s² 5p⁶
Iodine: (I)
Iodine is present in group seventeen. Its outer most valance shell have seven electrons. Iodine is the member of halogen family. It gain one electron to complete the octet. its atomic number is fifty three.
Electronic configuration:
I₅₃ = [Kr] 4d¹⁰ 5s² 5p⁵
Potassium: (K)
Potassium is present in group one. it is alkali metal. Its atomic number is nineteen. Its valance shell has one electron. Potassium loses its one valance electron and gets stable electronic configuration.
Electronic configuration:
K₁₉ = [Ar] 4s¹
Strontium: Sr
Strontium is present in group two. it is alkaline earth metal. its atomic number is thirty eight and have two valance electrons.
Electronic configuration:
Sr₃₈ = [Kr] 5s²
I believe that the answer is molecule
