The maximum number of D orbitals in a principal energy level is 5.
Answer:
<em>The molarity of the solution is 0,47 M</em>
Explanation:
Molarity is a concentration measurement that expresses the moles of solute (in this case NaOH) in 1 liter of solution (1000ml). First we calculate the mass of 1 mol of NaOH, to calculate the moles in 58.8 g of said compound:
Weight 1 mol NaOH= Weight Na + Weight O + Weight H=23 g + 16 g +1 g
Weight 1 mol NaOH= 40 g/mol
40 g ---1 mol NaOH
58,8g---x= (58,8g x 1 mol NaOH)/40g =1,47 mol NaOH
3,1 L solution ------1,47 mol NaOH
1 L solution --------x= (1 L solution x 1,47 mol NaOH)/3,1 L solution
<em>x= 0,47 mol NaOH ---> The molarity of the solution is 0,47 M</em>
Enthalpy change during the dissolution process = m c ΔT,
here, m = total mass = 475 + 125 = 600 g
c = <span>specific heat of water = 4.18 J/g °C
</span>ΔT = 7.8 - 24 = -16.2 oc (negative sign indicates that temp. has decreases)
<span>
Therefore, </span>Enthalpy change during the dissolution = 600 x 4.18 X (-16.2)
= -40630 kJ
(Negative sign indicates that process is endothermic in nature i.e. heat is taken by the system)
Thus, <span>enthalpy of dissolving of the ammonium nitrate is -40630 J/g</span>