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jarptica [38.1K]
4 years ago
6

(9443+45−9.9) (9443+45−9.9) ×8.4× 10 6

Chemistry
1 answer:
ozzi4 years ago
6 0
Booooooommmm!.................

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A 4.7g sample of ethanol is burned in a calorimeter containing 95.8 mL of water. If the initial temperature of the water is 29.1
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8 0
3 years ago
Number of Hydrogen Atoms in C18H34O2?
solniwko [45]
<span>There are 34 hydrogen atoms.
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6 0
4 years ago
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What is the mass in grams of 85.32 mL of blood plasma with a density of 1.03 g/mL
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3 0
3 years ago
how many grams of calcium sulfate are produced from 10 grams of calcium nitrate and how many grams of calcium sulfate are produc
AlekseyPX

Answer:  8.30 g of calcium sulfate are produced from 10 grams of lithium sulfate.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Ca(NO_3)_2=\frac{10g}{164g/mol}=0.061moles

\text{Moles of} Li_2SO_4=\frac{10g}{110g/mol}=0.091moles

Ca(NO_3)_2+Li_2SO_4\rightarrow 2LiNO_3+CaSO_4  

According to stoichiometry :

1 mole of Ca(NO_3)_2 require = 1 mole of Li_2SO_4

Thus 0.061 moles of Ca(NO_3)_2 will require=\frac{1}{1}\times 0.061=0.061moles  of Li_2SO_4

Thus Ca(NO_3)_2 is the limiting reagent as it limits the formation of product and Li_2SO_4 is the excess reagent.

As 1 mole of Ca(NO_3)_2 give = 1 mole of CaSO_4

Thus 0.061 moles of Ca(NO_3)_2 give =\frac{1}{1}\times 0.061=0.061moles  of CaSO_4

Mass of CaSO_4=moles\times {\text {Molar mass}}=0.061moles\times 136g/mol=8.30g

Thus 8.30 g of calcium sulfate are produced from 10 grams of lithium sulfate.

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