<span>389.88094 amu
First we look up the atomic mass of all elements contained in calcium iodate using the periodic table:
Ca: 40.078
I: 126.90447
O: 15.999
As an intermediate step we calculate the molecular mass of the ion IO3:
126.90447 + 3*15.999 = 174.90147
Then we calculate the mass of one calcium atom and 2 iodate ions:
2*174.90147 + 40.078 = 389.88094 amu</span>
The new pressure exerted by helium on its container is 2533.33 torr.
Boyle's law: For a fixed amount of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional. so PV= constant.
At constant temperature and moles,
P1V1 = P2V2.
The original sample is at 2atm torr and volume 5.00 L and then helium gas was compressed to 3.00 L
∴ P₁V₁ = P₂V₂
(2× 760 torr)(5.00 L ) = (3.00 L )(x torr),
x = 2533.33 torr.
P₂ = 2533.33 torr.
Therefore, the new pressure exerted by helium on its container is 2533.33 torr.
Learn more about pressure here:
brainly.com/question/15339700
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Answer: A
because electron mass is so small that they aren't accounted for the overall mass of an atom. Electrons are smaller than protons and neutrons.
Answer:
B. the amount of atoms you contain
The chemical formula for calcium hydroxide is Ca(OH)₂ and that of nitric acid is HNO₃. By these chemical formula it can be deduced that the number of equivalents per mole of Ca(OH)₂ is 2 because of 2 OH⁻ and for HNO₃ is 1 because of H⁺.
For the neutralization reaction, the number of equivalents should be equal.
V₁n₁ = V₂n₂
Substituting the known values and with the incorporation of the concept above,
(V₁)(0.0250 mol/L)(2 equivalents/mol) = (33.50 mL)(0.020 mol/L)(1 equivalent/mol)
V₁ = 13.4 mL
Hence, the volume of calcium hydroxide needed is approximately equal to 13.4 mL.
