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Karo-lina-s [1.5K]
3 years ago
12

Please I really need help:

Chemistry
2 answers:
12345 [234]3 years ago
6 0
The answer is C I think
puteri [66]3 years ago
4 0
<span>C. 159.70 Fe=55.85g/mol * 2 = 111.70 O=16.00g/mol * 3 = 48.00 +_______ 159.70</span>
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An element has atomic number 10 and an atomic mass of 20. How many neutrons are in the atom of this element?
Igoryamba

The answer is A. 10.

3 0
3 years ago
I anm definitely not a halogen. But if all you knew about me
Dmitriy789 [7]

The periodic law is a law relating the properties of the element with their

atomic numbers.

The element is <u>potassium, K</u>.

Reason:

By atomic mass, potassium is 39.10 g, while argon is 39.10 g.

Going by the atomic mass alone, potassium should come before argon in

the periodic table and therefore should be an halogen and not an alkali

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However, the number of protons in the potassium is 19, and therefore larger

than the number of protons in argon, which is argon.

Therefore, the element is <u>potassium, K</u>.

Learn more about the periodic law here:

brainly.com/question/2207821

5 0
1 year ago
Students conduct an experiment in which steel wool is burned in a closed test tube. The steel wool reacts with an amount of oxyg
Ksenya-84 [330]
The answer is 43.48g
6 0
3 years ago
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A certain substance X has a normal freezing point of 5.6 °C and a molal freezing point depression constant Kf-7.78 °C-kg·mol-1.
Harrizon [31]

Answer:

27.60 g urea

Explanation:

The <em>freezing-point depression</em> is expressed by the formula:

  • ΔT= Kf * m

In this case,

  • ΔT = 5.6 - (-0.9) = 6.5 °C
  • Kf = 7.78 °C kg·mol⁻¹

m is the molality of the urea solution in X (mol urea/kg of X)

First we<u> calculate the molality</u>:

  • 6.5 °C = 7.78 °C kg·mol⁻¹ * m
  • m = 0.84 m

Now we<u> calculate the moles of ure</u>a that were dissolved:

550 g X ⇒ 550 / 1000 = 0.550 kg X

  • 0.84 m = mol Urea / 0.550 kg X
  • mol Urea = 0.46 mol

Finally we <u>calculate the mass of urea</u>, using its molecular weight:

  • 0.46 mol * 60.06 g/mol = 27.60 g urea

7 0
3 years ago
Need helpppp please
Vladimir79 [104]

Answer:

message me so i can help you because i cant see the words

Explanation:

6 0
2 years ago
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