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Karo-lina-s [1.5K]
3 years ago
12

Please I really need help:

Chemistry
2 answers:
12345 [234]3 years ago
6 0
The answer is C I think
puteri [66]3 years ago
4 0
<span>C. 159.70 Fe=55.85g/mol * 2 = 111.70 O=16.00g/mol * 3 = 48.00 +_______ 159.70</span>
You might be interested in
SOMEONE PLS HELP
Gekata [30.6K]

Answer:

<h2>464.85 mL</h2>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we're finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

100.7 kPa = 100,700 Pa

95.1 kPa = 95,100 Pa

We have

V_2 =  \frac{100700 \times 439}{95100}  =  \frac{44207300}{95100}  \\  = 464.8506...

We have the final answer as

<h3>464.85 mL</h3>

Hope this helps you

6 0
3 years ago
La aspirina se prepara haciendo reaccionar ácido salicílico con exceso de anhídrido etanoico. En un experimento, 50.05 g de ácid
Tanya [424]

La aspirina se prepara haciendo reaccionar ácido salicílico con exceso de anhídrido etanoico. En un experimento, 50.05 g de ácido salicílico se convirtieron en 55.45 g de aspirina. ¿Cuál fue el porcentaje de rendimiento?

<em>In English:</em>

Aspirin is prepared by reacting salicylic acid with excess ethanoic anhydride. In one experiment, 50.05 g of salicylic acid was converted to 55.45 g of aspirin. What was the yield percentage?

Answer:

el rendimiento porcentual para la cantidad dada de ácido salicílico es 84.99 %

<em>In English:</em>

<em>the percent yield for the given amount of salicylic acid is </em><em>84.99%</em>

<em></em>

Explanation:

La ecuación química equilibrada para la reacción se puede escribir como:

C₇H₆O₃ + C₄H₆O₃    →    C₉H₈O₄ + HC₂H₃O₂

Para la reacción mostrada arriba; El reactivo limitante de la reacción es el ácido salicílico. Ahora; calcular el porcentaje de rendimiento; se espera que primero determinemos el rendimiento teórico de la reacción.

Entonces; la fórmula para calcular el porcentaje de rendimiento: \mathbf {= \frac{actual \ yield }{theoretical \ yield } *100 }  

El rendimiento teórico se determina de la siguiente manera:

50.05 g * 1 mol / 138.21 g / mol de C₇H₆O₃ * 1 mol de C₉H₈O₄ / 1 mol de C₇H₆O₃ * 180.157 g / mol de C₉H₈O₄ = 65.24 g de C₉H₈O₄

Porcentaje de rendimiento \mathbf {= \frac{55.45 }{65.24 } *100 }

Porcentaje de rendimiento = 84.99%

Por lo tanto, el porcentaje de rendimiento para la cantidad dada de ácido salicílico es 84.99%

<em>In English:</em>

<em>The balanced chemical eqaution for the reaction can be written as:</em>

<em>C₇H₆O₃ + C₄H₆O₃    →    C₉H₈O₄ + HC₂H₃O₂</em>

<em>For the reaction shown above;  The limiting reactant from the reaction is  salicylic acid. Now; to calculate the percentage yield ; we are expected to first determine the theoretical yield of the reaction. </em>

<em>So; the formula for calculating the percentage yield </em>\mathbf {= \frac{actual \ yield }{theoretical \ yield } *100 }<em>  </em>

<em />

<em>The theoretical yield is determined as follows:</em>

<em>50.05 g * 1 mol/ 138.21 g/mol of C₇H₆O₃ * 1 mol of C₉H₈O₄/ 1 mol of C₇H₆O₃ * 180.157 g/mol of C₉H₈O₄ = 65.24 g of C₉H₈O₄ is produced</em>

<em />

<em>Percentage yield </em>\mathbf {= \frac{55.45 }{65.24 } *100 }<em />

<em>Percentage yield = 84.99%</em>

<em />

<em>Thus, the percent yield for the given amount of salicylic acid is </em><em>84.99%</em>

7 0
4 years ago
The conversion of cyclopropane to propene in the gas phase is a first-order reaction with a rate constant of 6.7 x 10-4 s -1 at
denpristay [2]

Answer:

C_f=0.1755M

Explanation:

Hello,

Based on the information and the units of the given data, the integrated rate law turns out into:

\frac{dC}{dt}=-kC\\ C_f=C_0exp(-kt)\\C_f=0.25M*exp(-6.7x10^{-4}s^{-1}*8.8min*\frac{60s}{1min} )\\C_f=0.1755M

Best regards.

8 0
3 years ago
2. What would be the outcome of a unicellular organism that cannot maintain homeostasis? (1 point)
Juli2301 [7.4K]

Answer:

Option A = it dies

Explanation:

Homeostasis:

It is the ability of organisms to maintain the equilibrium in its internal environment in order to deal with external environmental changes.

If the unicellular organism cannot maintain the homeostasis it would die.

Importance of homeostasis:

It is constant chemical and physical condition of cell. The unicellular organisms in maintained homeostasis condition can grow and reproduce. They respond to the environment and transfer energy. It is the primary objective of unicellular organism other wise they would not survive.

It is very important for them because they totally rely on it and can perform the necessary functions of life.

While in case of multi cellular organisms all cells communicate with each other to maintain the homeostasis.

3 0
3 years ago
Mole-Atom Conversions
iragen [17]

Answer:

Explanation:

1) How many moles are 1.55 × 10²⁷ atoms of zinc?

Answer:

0.26 × 10⁴ mole

Explanation:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For  1.55 × 10²⁷ atoms of zinc:

1.55 × 10²⁷ atoms  × 1 mole/ 6.022 × 10²³ atoms

0.26 × 10⁴ mole

2) How many atoms are in 25.0 moles of calcium?

Answer:

150.55  × 10²³ atoms.

Explanation:

According to Avogadro number,

one mole of substance = 6.022 × 10²³ atoms

The number 6.022 × 10²³ is called Avogadro number.

For 25.0 moles of calcium:

one mole of calcium = 6.022 × 10²³ atoms

25.0 mole × 6.022 × 10²³ atoms /1 mole

150.55  × 10²³ atoms.

So 25.0 moles of calcium contain 150.55  × 10²³ atoms.

3) = How many atoms are in 0.35 moles of carbon?

Answer:

2.12× 10²³ atoms.

Explanation:

According to Avogadro number,

one mole of substance = 6.022 × 10²³ atoms

The number 6.022 × 10²³ is called Avogadro number.

For 0.35 moles of carbon:

one mole of carbon = 6.022 × 10²³ atoms

0.35 mole × 6.022 × 10²³ atoms /1 mole

2.12× 10²³ atoms.

So 0.35 moles of carbon contain 2.12× 10²³ atoms.

4 ) How many moles are 7.6 × 10²⁴ atoms of hellium?

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For  7.6 × 10²⁴ atoms of hellium:

7.6 × 10²⁴ atoms × 1 mole/ 6.022 × 10²³ atoms

12. 6  mole

<em>Mass - Mole conversion:</em>

How many moles in 28.0 gram of oxygen?

Answer:

1.75 mol

Explanation:

Given data:

Mass of oxygen = 28 g

Number of moles = ?

Solution:

Formula:

Number of moles = mass/ molar mass

Molar mass of oxygen = 16 g/mol

Now we will put the values in formula:

Number of moles = 28 g / 16 g/mol

Number of moles = 1.75 mol

So 28 g of oxygen contain 1.75 moles.

3)  Find the number of moles of argon in 452 g?

Answer:

11.31 mol

Explanation:

Given data:

Mass of argon = 452 g

Number of moles = ?

Solution:

Formula:

Number of moles = mass/ molar mass

Molar mass of argon= 39.95 g/mol

Now we will put the values in formula:

Number of moles =  452 g /39.95 g/mol

Number of moles = 11.31 mol

So 452 g of argon contain 11.31 moles.

2) What is the mass of 5.0 moles of iron?

Answer:

Mass = 279.25 g

Explanation:

Given data:

Mass of iron = ?

Number of moles of iron = 5.0 mol

Solution:

Formula:

Mass = number of moles × molar mass

Molar mass of iron = 55.85 g/mol

Now we will put the values in formula:

Mass = number of moles × molar mass

Mass = 5 mol ×  55.85 g/mol

Mass = 279.25 g

4) Find the grams of 16.5 mole of hydrogen?

Answer:

Mass = 16.632 g

Explanation:

Given data:

Mass of hydrogen = ?

Number of moles of hydrogen = 16.5 mol

Solution:

Formula:

Mass = number of moles × molar mass

Molar mass of hydrogen = 1.008 g/mol

Now we will put the values in formula:

Mass = number of moles × molar mass

Mass = 16.5 ×  1.008 g/mol

Mass = 16.632 g

7 0
4 years ago
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