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telo118 [61]
3 years ago
8

How is counting a truckload of pennies like counting the atoms in 10.0 g of aluminum? How is it different?

Chemistry
1 answer:
Anestetic [448]3 years ago
5 0

Answer:

Explanation:

A truckload of pennies is quite a very large amount of problem to solve. A truck can carry a lot of coins which can be up to several millions in number approximately.

This is similar to counting the number of atoms in 10.0g of aluminium.

 In a mole of any substance, there are 6.02 x 10²³ atoms.

            number of moles  = \frac{mass}{molar mass}

                    molar mass of Al  = 27g/mole

           number of moles  = \frac{10}{27}   = 0.37moles

  Number of atoms  = 0.37 x 6.02 x 10²³ = 2.23 x 10²³ atoms

In 10g of aluminium, there are 2.23 x 10²³ atoms. It is even much more tedious to count.

Difference;

We can see the pennies in the truckload. They are discrete. It is impossible to see atoms in a substance this way.

Also, the number of atoms in 10g of aluminium is more than that of pennies in a truckload.

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What is the electron configuration for vanadium (V)? The Periodic Table A. 1s22s22p63s23p64s24d3 B. 1s22s22p63s23p63d5 C. 1s22s2
kramer

The electronic configuration for vanadium (V) in the periodic table is as follows: 1s2 2s2 2p6 3s2 3p6 4s2 3d3 (option D).

<h3>What is electronic configuration?</h3>

Electronic configuration is the the arrangement of electrons in an atom, molecule, or other physical structure like a crystal.

Vanadium is the 23rd element on the periodic table and has chemical symbol V with atomic number 23. It is a transition metal, used in the production of special steels.

This suggests that the electronic configuration of Vanadium will be written as follows: 1s2 2s2 2p6 3s2 3p6 4s2 3d3

Therefore, the electronic configuration for vanadium (V) in the periodic table is as follows: 1s2 2s2 2p6 3s2 3p6 4s2 3d3.

Learn more about electronic configuration at: brainly.com/question/14283892

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2 years ago
Electrons are always shared evenly during covalent bonding.<br> O True<br> False
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Answer:

False

Explanation:

There are two types of covalent bonding: polar covalent boding and nonpolar covalent bonding. During polar covalent bonding, the electrons are not shared evenly. This is due to the electronegativity differences between the two atoms. During nonpolar covalent bonding, the electrons are shared evenly.

8 0
2 years ago
Know how you would determine the percent yield of a reaction if you have the given amount of the reactants and the amount of the
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First, use the given amount of reactants to calculate the theoretical amount of products that should be formed based on stoichiometry. Next, divide the actual amount of obtained product by that theoretical amount, and multiply by 100%. This gives the percent yield of the reaction.
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4 years ago
Imagine if Rutherford conducted his scattering experiment, and his prediction about the movement of alpha particles held true Wh
IRINA_888 [86]

Answer:

The plum pudding model would have to be true as well because it shows that electrons are scattered within an atom.

Explanation:

I took the test and got it right :)

4 0
3 years ago
Fe2O3 + CO --&gt; Fe + CO2
satela [25.4K]

Answer:

The answer to your question is

1.-Fe₂O₃

2.- 280 g

3.- 330 g

Explanation:

Data

mass of CO = 224 g

mass of Fe₂O₃ = 400 g

mass of Fe = ?

mass of CO₂

Balanced chemical reaction

                       Fe₂O₃   + 3CO    ⇒  2Fe  +   3CO₂

1.- Calculate the molar mass of Fe₂O₃ and CO

Fe₂O₃ = (56 x 2) + (16 x 3) = 160 g

CO = 12 + 16 = 28 g

2.- Calculate the proportions

theoretical proportion Fe₂O₃ /3CO = 160/84 = 1.90

experimental proportion Fe₂O₃ / CO = 400/224 = 1.78

As the experimental proportion is lower than the theoretical, we conclude that the Fe₂O₃ is the limiting reactant.

3.-     160 g of Fe₂O₃  --------------- 2(56) g of Fe

         400 g of Fe₂O₃ ---------------  x

         x = (400 x 112) / 160

        x = 280 g of Fe

4.-      160 g of Fe₂O₃  --------------- 3(44) g of CO₂

          400 g of Fe₂O₃  --------------  x

          x = (400 x 132)/160

         x = 330 gr

3 0
3 years ago
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