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telo118 [61]
3 years ago
8

How is counting a truckload of pennies like counting the atoms in 10.0 g of aluminum? How is it different?

Chemistry
1 answer:
Anestetic [448]3 years ago
5 0

Answer:

Explanation:

A truckload of pennies is quite a very large amount of problem to solve. A truck can carry a lot of coins which can be up to several millions in number approximately.

This is similar to counting the number of atoms in 10.0g of aluminium.

 In a mole of any substance, there are 6.02 x 10²³ atoms.

            number of moles  = \frac{mass}{molar mass}

                    molar mass of Al  = 27g/mole

           number of moles  = \frac{10}{27}   = 0.37moles

  Number of atoms  = 0.37 x 6.02 x 10²³ = 2.23 x 10²³ atoms

In 10g of aluminium, there are 2.23 x 10²³ atoms. It is even much more tedious to count.

Difference;

We can see the pennies in the truckload. They are discrete. It is impossible to see atoms in a substance this way.

Also, the number of atoms in 10g of aluminium is more than that of pennies in a truckload.

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The equivalent weight of M is approximately 31.8 g

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Explanation:

The given parameters are;

The percentage of the the metal M in in the chloride = 47.25%

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47.25% of the mass of MClₓ = Mass of M = W

Therefore, we have;

\dfrac{0.4725}{W} = \dfrac{1}{W + 35.5 \cdot x}

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W - 0.4725·W  = 16.77·x

0.5275·W = 16.77·x

W/x = 16.77/0.5275 = 31.799 = The equivalent weight of M

The equivalent weight of M = 31.799 ≈ 31.8 g

Given that 1 gram of M is displaced by 0.88 gram of N, then the equivalent weight of N that will displace 31.799 = 0.88 × 31.799 ≈ 27.98 g

The equivalent weight of N = 27.98 g.

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