Answer:
Density of steel = 80.73 gm/
Step-by-step explanation:
The figure is made up of cuboid and square pyramid.
Height of cuboid, h = 9 cm
Length of cuboid, l = 6 cm
Width of cuboid, w = 6 cm
Volume of cuboid is given by the formula:
Density of Wood , 
= 0.68g/
We know that formula of Density is:
Putting the values:
Total weight = 
970 = 220.32 
= 749.68 gm
Volume of pyramid is given as:
Base is a square with side 6 cm
Density of Steel/Pyramid:
(-2x^3y^4z^0)^4
<span><span><span>(−2<span>x^<span><span>3</span><span>^</span></span></span><span>y<span><span>4</span><span></span></span></span>×^1)</span><span><span>4</span><span>
</span></span></span><span>
(-2x^3y^4)^4
(2x^3y^4)^4
2^4(x^3)^4(y^4)^4
16(x^3)^4(y^4)^4
16x^12(y^4)^4</span></span>
We are given the equation of a line
y = -2x + 1
We have to find the value of y at three different values of x i.e. x = 0, -3 and 1
In order to find the value of y at any given x, simply replace x by that number.
So, for x=0, we will replace x by 0 to find the value of y. So y will be:
y = -2(0) + 1
y = 1
This can be expressed as an ordered pair as (0,1)
Similarly for x=-3, we get
y = -2(-3) + 1 = 6 + 1
y = 7
This can be expressed as an ordered pair as (-3, 7)
And, finally for x=1, we get:
y= -2(1) + 1 = -2 + 1
y = -1
This can be expressed as an ordered pair as (-1, -1)
Answer:
9.00 square units
Step-by-step explanation:
The width of the interval is 4 − 0 = 4. Divided by 4 equal subintervals, the width of each subinterval is 4/4 = 1.
The subintervals are:
0 ≤ x ≤ 1
1 ≤ x ≤ 2
2 ≤ x ≤ 3
3 ≤ x ≤ 4
MRAM is midpoint rectangular approximation method. So we use the midpoints of each interval to find the height of the rectangle:
f(0.5) = (0.5)² − 4(0.5) + 5 = 3.25
f(1.5) = (1.5)² − 4(1.5) + 5 = 1.25
f(2.5) = (2.5)² − 4(2.5) + 5 = 1.25
f(3.5) = (3.5)² − 4(3.5) + 5 = 3.25
So the total approximate area is:
A = 3.25 + 1.25 + 1.25 + 3.25
A = 9.00
Graph: desmos.com/calculator/x8dcibqszo
