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ella [17]
3 years ago
12

A jet plane lands with a velocity of 100 m/s and can accelerate at a maximum of -9.0 m/s2 as it comes to rest. The minimum time

needed before it can come to rest is seconds.
Physics
1 answer:
ale4655 [162]3 years ago
6 0

Explanation:

That must be the right ans.

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PLEASE HELP ME Color corresponds to the ______________ of light waves. wave speed cycles wavelength
lorasvet [3.4K]
Wavelength. Each wavelength is a certain color. For instance, shorter wavelengths (like 470nm) will be blue or violet, while longer wavelengths (like 650nm) will be red. Hope this helps! :)
5 0
3 years ago
1. A 59 kg person is in a vehicle travelling at 41 m/s. The vehicle runs into a telephone pole. At impact, it
Tems11 [23]

Answer:

a. 12,600 N

b. 1290 kg

Explanation:

a. Impulse = change in momentum

F Δt = m Δv

F (0.192 s) = (59 kg) (0 m/s − 41 m/s)

F = -12,600 N

b. F = mg

12,600 N = m (9.8 m/s²)

m = 1290 kg (or 2,830 lbs)

5 0
3 years ago
What happens to an object's mass as the object's acceleration increases but the force stays the same
Iteru [2.4K]

Answer:

the mass stays the same

Explanation:

the more mass the faster

6 0
3 years ago
Read 2 more answers
Convert 1 mm to meters using scientific notation. Include units in your answer.
miskamm [114]

Answer:

1.0 x 10^-3 m

Explanation:

1mm = (1/1000) m = 0.001m = 1.0 x 10^-3m (because to get 1.0, you have to  movi the decimal point in the "0.001" three spots over to the right)

3 0
2 years ago
The moment of inertia for a 5500 kg solid disc is 12100 kg-m^2. Find the radius of the disc? (a) 2.111 m (b) 2.579 m (c) 1.679
Soloha48 [4]

Answer:

The radius of the disc is 2.098 m.

(e) is correct option.

Explanation:

Given that,

Moment of inertia I = 12100 kg-m²

Mass of disc m = 5500 kg

Moment of inertia :

The moment of inertia is equal to the product of the mass and square of the radius.

The moment of inertia of the disc is given by

I=\dfrac{mr^2}{2}

Where, m = mass of disc

r = radius of the disc

Put the value into the formula

12100=\dfrac{5500\times r^2}{2}

r=\sqrt{\dfrac{12100\times2}{5500}}

r= 2.098\ m

Hence, The radius of the disc is 2.098 m.

8 0
2 years ago
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