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Bad White [126]
3 years ago
15

How many minutes does light need to travel from the sun to Jupiter?

Physics
1 answer:
nydimaria [60]3 years ago
3 0

Light travels at a speed of 299,792 kilometers per second; 186,287 miles per second

Mercury it will take 193.0 seconds(3.2 minutes)

Venus it will take 360.0 seconds(6.0 minutes)

Earth it will take 499.0 seconds(8.3 minutes)

Mars  It will take 759.9 seconds(12.6 minutes)

Jupiter  It will take 2595.0 seconds(43.2 minutes)

Saturn it will take 4759.0 seconds(79.3 minutes)

Uranus it will take 9575.0 seconds(159.6 minutes)

Neptune it will take 14998.0 seconds(4.1 hours)

Pluto  it will take 19680.0 seconds(5.5 hours)

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A slab of glass has a 0.600 cm thick layer of water on top of it. A light ray strikes the water at an incident angle of 59.0°. A
Dimas [21]

Answer:

49.63 degree

Explanation:

thickness of glass slab, t = 0.6 cm

angle of incidence = 59 degree

Let r be the angle of refraction

The refractive index of glass, ng = 3/2

refractive index of water, nw = 4/3

refarctive index of glass with respect to water = ng / nw = 3 /2 ÷ 4 /3 = 9 / 8

So, by use of Snell's law

Refractive index of glass with respect to water = Sin i / Sin r

9 / 8 = Sin 59 / Sin r

9 / 8 = 0.857 / Sin r

Sin r = 0.7619

r = 49.63 degree

4 0
3 years ago
You are 12 miles north of your base camp when you begin walking north at a speed of 2 miles per hour. What is your location, rel
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If you walk at a pace of 2 miles per hour for 5 hours, you should have walked 10 miles. You would be 2 miles away from your base camp. 
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What is the best way to start a summary paragraph
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Start with what the paragraph is about and put it basically in your own words
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What causes charges to move in a circuit?
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A )voltage
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A rubber-wheeled 50 kg cart rolls down a 35 degree concrete incline. Coefficient of rolling friction between rubber and concrete
lapo4ka [179]

Answer:

(a) 5.62 m/s²

(b) 5.46 m/s²

Explanation:

The given values are:

mass,

m = 50 kg

angle

= 35°

(a)

If friction neglected,

⇒ F_x=mgSin \theta=ma

⇒ a_x=gSin \theta

       =9.8 \ Sin35^{\circ}

       =5.62 \ m/s^2

(b)

If friction present,

⇒ F_x=mgCos \theta

⇒ F_x=mgSin \theta-\mu_r mgCos \theta

⇒ a=gSin \theta-\mu_rgCos \theta

      =9.8 \ Sin35^{\circ}-0.02\times 9.8 \ Cos30^{\circ}

      =5.46 \ m/s^2

8 0
3 years ago
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