Answer:
8.77 grams NaC
Explanation:
To find the mass of NaCl, you need to (1) use the molarity equation to find moles, then (2) calculate the molar mass of NaCl (via the periodic table), and then (3) convert moles NaCl to grams (via molar mass). The final answer should have 3 sig figs because the given values also have 3 sig figs.
(Step 1)
Molarity (M) = moles / volume (L)
0.250 M = moles / 0.600 L
(0.250 M) x (0.600 L) = moles
0.150 = moles
(Step 2)
Molar Mass (NaCl): 22.99 g/mol + 35.45 g/mol
Molar Mass (NaCl): 58.44 g/mol
(Step 3)
0.150 moles NaCl 58.44 g
--------------------------- x ------------------- = 8.77 grams NaCl
1 mole
Answer:
Explanation:
Ok, so I suppose you meant NaCl. But ok:
So we have the formula moles = grams/MM, where MM is molar mass. The molar mass of NaCl is 58.44 g/mol. That means that 55/58.44 is the number of moles which appears to be 0.94 moles.
Answer
A reactant is a substance that is present at the start of a chemical reaction. These are what breakdown to form products and its always to the right.
A product is a substance that is present at the end of a chemical reaction. These are what are formed after the reactants are broken down, the end result.
Answer:
i think that sonoran toads would prosper and wood frogs would disappear
Explanation:
because of the provided information
Answer:
Approximately 2000 J.
General Formulas and Concepts:
<u>Thermodynamics</u>
Specific Heat Formula: q = mcΔT
- <em>q</em> is heat (in J)
- <em>m</em> is mass (in g)
- <em>c</em> is specific heat (in J/g °C)
- ΔT is change in temperature (in °C or K)
Explanation:
<u>Step 1: Define</u>
<em>Identify variables</em>
[Given] <em>c</em> = 0.897 J/g °C
[Given] <em>m</em> = 79 g
[Given] ΔT = 28°C
[Solve] <em>q</em>
<em />
<u>Step 2: Solve for </u><em><u>q</u></em>
- Substitute in variables [Specific Heat Formula]: q = (79 g)(0.897 J/g °C)(28 °C)
- Multiply [Cancel out units]: q = (70.863 J/°C)(28 °C)
- Multiply [Cancel out units]: q = 1984.16 J
<u>Step 3: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs as our lowest.</em>
1984.16 J ≈ 2000 J
