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3 years ago

Which of the following statements is true?

Chemistry

2 answers:

ivann1987 [24]3 years ago

7 0

Answer:

U-235 is an isotope of uranium

Explanation:

The most stable form of uranium isotopes is 235. (0.7198–0.7202%)

Citrus2011 [14]3 years ago

6 0

Answer:

U-235 is a isotope of Uranium

Explanation:

We know, Uranium is naturally occurring element that has radioactive nature and has no stable isotope. Uranium is made up of 3 major isotopes Which are U-238 found in 99.27–99.27% natural abundance, U-235 found in 0.72% and U-234 found in 0.0051% abundance.

The list of isotopes is Uranium-233, Uranium-234 and Uranium-235. Hence, U-235 is a isotope of Uranium is the correct statement.

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Why do atmoic numbers increase from left to right across any given row of the periodic table

stira [4]

They have increased number of protons which is the atomic number.

4 0

2 years ago

When 3.51 g of phosphorus was burned in chlorine, the product was a phosphorus chloride. Its vapor took 1.77 times as long to ef

kumpel [21]

Answer:

molar mass of the phosphorus chloride = 138.06 g/mol

Explanation:

mass of phosphorus will be the same as mass of CO2, since it is stated that they are of equal amount.

mass = 3.51 g

lets assume that it took the CO2 1 sec to effuse, then the time taken by the phosphorus chloride will be 1.77 sec

From this we can say that

rate of effusion of CO2 = 3.51/1 = 3.51 g/s

rate of effusion of the phosphorus chloride = 3.51/1.77 = 1.98 g/s

From graham's equation of effusion,

$\frac{Rc}{Rp}$ = $\sqrt{\frac{Mp\\}{Mc} }$

Rc = rate of effusion of CO2 = 3.51 g/s

Rp = rate of effusion of phosphorus chloride = 1.98 g/s

Mc = molar mass of CO2 = 44.01 g/mol

Mp = molar mass of the phosphorus chloride = ?

Imputing values into the equation, we have

$\frac{3.51}{1.98}$ = $\sqrt{\frac{Mp\\}{44.01} }$

1.77 = $\frac{\sqrt{Mp} }{6.64}$

11.75 = $\sqrt{Mp}$

Mp = $11.75^{2}$

Mp = molar mass of the phosphorus chloride = 138.06 g/mol

5 0

3 years ago

What volume will 0.875 moles of Kr occupy at STP

umka21 [38]

V = nRT/P = (0.875)(0.082057)(273)/(1) = 19.6 L

6 0

3 years ago

The reaction A( g ) ⇌ 2 B( g ) A(g) ⇌ 2 B(g) has an equilibrium constant of K = 0.010 K = 0.010. What is the equilibrium constan

Over [174]

Answer:

K = 10

Explanation:

Using Hess's law, it is possible to obtain the equilibrium constant, K, of a reaction using K of similar reactions. For example:

If A ⇄ B K = X

B ⇄ A K = 1/X

2A ⇄ 2B K = X².

Thus, if A(g) ⇄ 2B(g) K = 0.010

2B(g) ⇄ A(g) K = 1 / 0.010; K = 100

B(g) ⇄ A(g) K = √100 = 10

5 0

3 years ago

The elements X and Y combine in different ratios to form four different types of compounds: XY, XY2, XY3, and XY4. Consider that

Law Incorporation [45]

Answer:

Ratios in order of increasing value ; The ratio of the mass ratio of Y to X in XY2 to the mass ratio of Y to X in XY, The ratio of the mass ratio of Y to X in XY3 to the mass ratio of Y to X in XY, The ratio of the mass ratio of Y to X in XY4 to the mass ratio of Y to X in XY

1) Mass ratio = 3

2) Mass ratio = 2

3) Mass ratio = 4

Explanation:

The detailed and step by step calculation is shown in the attachment.

3 0

3 years ago