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Anna007 [38]
3 years ago
8

Can anyone help me pleas

Chemistry
2 answers:
solniwko [45]3 years ago
7 0

0 electrons would be in the third shell. Because due to the fact that it only has 6 protons means that it is a Carbon element. There would be 2 electrons in the first shell, 4 in the second, and 0 in the third.

loris [4]3 years ago
3 0

In a neutral atom, the number of electrons will equal the number of protons


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Paraphin [41]

Answer:

2.01588 grams

Explanation:

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What is the percent by volume of alcohol, in a solution containing 24 mL of alcohol dissolved in 90 mL of water?
Dmitry [639]

Answer:

use this formula it will help u .

Explanation:

If 60 ml of ethanol is diluted to a final volume of 400 ml, you create a 35 % ethanol solution.

First, realize that you creating a solution with that contains a polar solute (ethanol) with a polar solvent (water). Remember that "like dissolves like."

If you pour 60 ml of ethanol in a volumetric flask, you add 340 ml of water to dilute this solution to a final volume of 400 ml.

Volumetric flasks are designed to make or dilute solutions to specified final volume.

Since you have 60 ml of ethanol in a total solution of 400 ml, the percentage of ethanol is 35 %.

This result is obtained in the following manner.

ml/400. ml. = .35

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3 0
3 years ago
For an aqueous solution of sodium chloride (NaCl) .Determine the molarity of 3.45L of a solution that contains 145g of sodium
worty [1.4K]
Molar mass NaCl = 58.44 g/mol

number of moles:

mass NaCl / molar mass

145 / 58.44 => 2.4811 moles of NaCl

Volume = 3.45 L

Therefore :

M = moles / volume in liters:

M = 2.4811 / 3.45

M = 0.719 mol/L⁻¹

hope this helps!
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Which is NOT a form of electromagnetic radiation?
sertanlavr [38]
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6 0
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Read 2 more answers
PLEASE HELPPP!!!!
aksik [14]

Answer:

b. 11.90 Liters

Explanation:

  • The balanced equation for the mentioned reaction is:

<em>3O₂ + 4Al → 2Al₂O₃,</em>

It is clear that 3.0 moles of O₂ react with 4.0 moles of Al to produce 2.0 Al₂O₃.

  • Firstly, we need to calculate the no. of moles (n) of 36.12 g of Al₂O₃:

<em>n = mass/molar mass</em> = (44.18 g)/(101.96 g/mol) = <em>0.4333 mol.</em>

<u><em>using cross multiplication:</em></u>

3.0 mol of O₂ produces → 2.0 mol of Al₂O₃.

??? mol of O₂ produces → 0.4333 mol of Al₂O₃.

<em>∴ The no. of moles of O₂ needed to produce 36.12 grams of Al₂O₃</em> = (3.0 mol)(0.4333 mol)/(2.0 mol) = <em>0.65 mol.</em>

  • Now, we can find the volume of O₂ used during the experiment:

We can use the general law of ideal gas: <em>PV = nRT.</em>

where, P is the pressure of the gas in atm (P = 1.3 atm).

V is the volume of the gas in L (V = ??? L).

n is the no. of moles of the gas in mol (n = 0.65 mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (T = 290 K).

<em>∴ V = nRT/P </em>= (0.65 mol)(0.0821 L.atm/mol.K)(290 K)/(1.3 atm) = <em>11.9 L.</em>

<em>So, the right choice is: b. 11.90 Liters.</em>

8 0
3 years ago
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