Ca as a limiting reactant
<h3>Further explanation</h3>
Given
8 g Calcium
50 g HCl
<h3>Required</h3>
Limiting reactant
Solution
Reaction
Ca + 2HCl → CaCl₂ + H₂
mol Ca (Ar = 40 g/mol) :
= mass : Ar
= 8 g : 40 g/mol
= 0.2
mol HCl (MW= 36.5 g/mol) :
= mass : MW
= 50 g : 36.5 g/mol
= 1.37
Mol : coefficient reactants :
Ca = 0.2/1 = 0.2
HCl = 1.37/2 = 0.685
Ca as a limiting reactant(smaller ratio)
The answer is [Boron]
I had this answer on my Chemistry test!
Answer:
Explanation:
Given parameters;
pH = 8.74
pH = 11.38
pH = 2.81
Unknown:
concentration of hydrogen ion and hydroxyl ion for each solution = ?
Solution
The pH of any solution is a convenient scale for measuring the hydrogen ion concentration of any solution.
It is graduated from 1 to 14
pH = -log[H₃O⁺]
pOH = -log[OH⁻]
pH + pOH = 14
Now let us solve;
pH = 8.74
since pH = -log[H₃O⁺]
8.74 = -log[H₃O⁺]
[H₃O⁺] = 10⁻![^{8.74}](https://tex.z-dn.net/?f=%5E%7B8.74%7D)
[H₃O⁺] = 1.82 x 10⁻⁹mol dm³
pH + pOH = 14
pOH = 14 - 8.74
pOH = 5.26
pOH = -log[OH⁻]
5.26 = -log[OH⁻]
[OH⁻] = 10![^{-5.26}](https://tex.z-dn.net/?f=%5E%7B-5.26%7D)
[OH⁻] = 5.5 x 10⁻⁶mol dm³
2. pH = 11.38
since pH = -log[H₃O⁺]
11.38 = -log[H₃O⁺]
[H₃O⁺] = 10⁻![^{11.38}](https://tex.z-dn.net/?f=%5E%7B11.38%7D)
[H₃O⁺] = 4.17 x 10⁻¹² mol dm³
pH + pOH = 14
pOH = 14 - 11.38
pOH = 2.62
pOH = -log[OH⁻]
2.62 = -log[OH⁻]
[OH⁻] = 10![^{-2.62}](https://tex.z-dn.net/?f=%5E%7B-2.62%7D)
[OH⁻] =2.4 x 10⁻³mol dm³
3. pH = 2.81
since pH = -log[H₃O⁺]
2.81 = -log[H₃O⁺]
[H₃O⁺] = 10⁻![^{2.81}](https://tex.z-dn.net/?f=%5E%7B2.81%7D)
[H₃O⁺] = 1.55 x 10⁻³ mol dm³
pH + pOH = 14
pOH = 14 - 2.81
pOH = 11.19
pOH = -log[OH⁻]
11.19 = -log[OH⁻]
[OH⁻] = 10![^{-11.19}](https://tex.z-dn.net/?f=%5E%7B-11.19%7D)
[OH⁻] =6.46 x 10⁻¹²mol dm³
The trophosphere contains the most water vapor!
Gamma rays because the kill every living cell and they have the shortest waves that are dangerous