Answer : The correct option is, (A) silver ion gains electrons more easily and is a stronger oxidizing agent than a chromium(III) ion.
Explanation :
The given half reaction are :
1st half reaction : 
The reduction potential of this reaction = +0.80 V
2nd half reaction : 
The reduction potential of this reaction = -0.74 V
From the reduction potentials, we conclude that the reaction which have positive reduction potential, they will gain electrons more easily and reduced itself and act as a stronger oxidizing agent.
Or we can say that the reaction which have negative reduction potential, they will lose electrons more easily and oxidized itself and act as a stronger reducing agent.
The reduction potential of 1st half reaction is positive and 2nd half reaction is negative.
Therefore, the silver ion gains electrons more easily and is a stronger oxidizing agent than a chromium(III) ion.
Answer:
A monosaccharide that contains 4 carbon atoms, one of which is in an aldehyde group, is classified as an aldotetrose.
Explanation:
A tetrose is a monosaccharide with 4 carbon atoms.
They have either an aldehyde functional group in position 1 (aldotetroses).
or a ketone functional group in position 2 (ketotetroses).
So, A monosaccharide that contains 4 carbon atoms, one of which is in an aldehyde group, is classified as an aldotetrose.
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There are 78 neutrons in Cesium but there is no option of 78 so closely related is 75
Answer:
If each element can be identified by its spectrum then the composition of an unknown star can be determined
Explanation:
The chemical nature of the elements is that they absorb specific wavelength of light depending on their atom. By spectral analysis of the spectrum of emitted light by a body, the body's composition can therefore be determined. As such in order to determine the composition of distant bodies such as planets, stars and other celestial bodies scientists usually make use of spectroscopy.
