Subtract 10x
10x + y = -19
10x + 3y = -17
You would get:
-2y = -2
Two negatives make a positive number! Divide
y = 1
Plug in
10x + (1) = -19
10x = -20
Divide
x = -2
Your solutions are
x = -2
y = 1
Answer:
a) 229 and 305 days
b) 229 days or less
c) 305 days or more
Step-by-step explanation:
The Empirical Rule(68-95-99.7 rule) states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 267
Standard deviation = 19
(a) Between what values do the lengths of the middle 95% of all pregnancies fall?_____________and___________days
By the Empirical rule, 95% of all pregnancies fall within 2 standard deviations of the mean.
So
267 - 2*19 = 229 days
to
267 + 2*19 = 305 days
(b) How short are the shortest 2.5% of all pregnancies?______days or less
95% of all pregnancies fall within 2 standard deviations of the mean. The other 5% are more than 2 standard deviations from the mean. Since the distribution is symmetric, 2.5% is more than 2 standard deviations below the mean(shortest 2.5%) and 2.5% is more than 2 standard deviations above the mean(longest 2.5%). So
267 - 2*19 = 229 days
c) How long do the longest 2.5% of pregnancies last?________days or more
Explanation in b)
267 + 2*19 = 305 days
Answer:
27.70
Step-by-step explanation:
you have to do 87 divided by the pi you only have to do 3.14 as the pi.
PART 1:55-21=35
35/60=<span>.58333
360</span>×<span>.58333 =210 DEGREES
</span><span>210*pi/180 = 3.665 RADIANS
PART 2: </span><span>(pi) x 2r x .58333
</span><span>3.14 x 12 x .58333 = 21.98 in
PART 3: </span><span>5π inches = 5 x 3.14 = 15.708 inches / 6 in radius = 2.618 radians
PART 4: </span><span>2.618 radians * 180/pi = 150° </span>
<span> x coordinate = 6(cos 150°) = -5.196 </span>
<span> y coordinate = 6(sin 150°) = 3 </span>
<span> the coordinates would be (-5.196, 2)</span>
