Answer: V = 15 m/s
Explanation:
As stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. The observed frequency the car will be experiencing will be addition of the two frequency. That is,
F = 2.1 × 10^10 + 1030 = 2.100000103×10^10Hz
Using doppler effect formula
F = C/ ( C - V) × f
Where
F = observed frequency
f = source frequency
C = speed of light = 3×10^8
V = speed of the car
Substitute all the parameters into the formula
2.100000103×10^10 = 3×10^8/(3×10^8 -V) × 2.1×10^10
2.100000103×10^10/2.1×10^10 = 3×108/(3×10^8 - V)
1.000000049 = 3×10^8/(3×10^8 - V)
Cross multiply
300000014.7 - 1.000000049V = 3×10^8
Collect the like terms
1.000000049V = 14.71429
Make V the subject of formula
V = 14.71429/1.000000049
V = 14.7 m/s
The speed of the car is 15 m/s approximately
The answer is actually 1 & 17, maybe you meant to put 1&17 as option b
Answer:
1.8x10⁻³m
Explanation:
From the question above, the following information was used to solve the problem.
wavelength λ = 4.5x10⁻⁷m
Length L = 2.0 meters
distance d = 5 x 10₋⁴m
ΔY = λL/d
= 4.5x10⁻⁷m (2) / 5 x 10₋⁴m
= 0.00000045 / 0.0005
= 0.0000009/0.0005
= 0.0018
= 1.8x10⁻³m
from the solution above The separation between two adjacent bright fringes is most nearly 1.8x10⁻³m
thank you!
It is a mechanical wave and cannot travel through a vacuum.
