Hi! Let's see.
<h3><u>TOPIC: Kinetic Energy.</u></h3>
Explanation:
Data:
- Mass(m) = 2.1 kilograms
- Speed(v) = 30 m/s
- Kinetic Energy(Ek) = ?
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Use the kinetic energy formula:
Replace by the data:
We multiply speed squared:
Multiply in the numerator, without forgetting the units:
Both numerator and denominador operations are divided:
Answer: The kinetic energy is <u>945 Joules.</u>
Cordially Alejanndraax. Greetings!
Answer: 4.9 x 10-3 N
Explanation:
A = 500cm^2 = 5 x 10^-2 m^2
V = 5 m/s
R = 10^-3 g/cm^2.sec = 10^-2kg/m^2 . sec
Prain water = R / V = 10^-2 / 5 = 2 x 10-3 kg/m^3
For the stationary bowl,
dm/dt =pAv= RA
F= dp/dt = (dm/dt) v = RAv = 2.5 x 10^-3 N
Bowl moving upwards to speed u = 2 m/s
dm/dt = pA ( v + u) / v
F = dp/dt = (dm/dt)(v+u) = RA (v+u)^2 / v = 4.9 x 10^-3 N
Answer:
(from top to bottom)
350 N, 80 kg, 10 m/s^2, 80 kg, -15 m/s^2, -3000 N
Explanation:
Force = Mass*Acceleration (aka F = ma)
Using algebra, you can find the variables/unknown values.
Answer:
Under assumption that all food energy that needs the horse is transformed into work, then the horse needs approximately 3 megajoules of food energy to work for 1 hour.
Explanation:
Since horse is working steadily, the power experimented by the horse (
), measured in watts, is at constant rate. Then, the work needed by the horse (
), measured in joules, is equal to that power multiplied by time (
), measured in seconds. That is:
(1)
If we know that
and
, then the work needed for the horse is:



Under assumption that all food energy that needs the horse is transformed into work, then the horse needs approximately 3 megajoules of food energy to work for 1 hour.
Your question is asked in a confusing way. Can you share more information about the equation?