Deposits of gold can be found in the deep ocean. Please select the best answer from the choices provided T F

Physics

2 answers:

Igoryamba3 years ago

7 0

In some cases true, and in others false. but it is true

Setler [38]3 years ago

5 0

Answer: True

The excavation of gold from the deep oceanic vents made possible from the Atlantic and north Pacific oceans. Approximately 100 metric million tons of gold has been excavated from these oceans. Also, the undissolved gold in the seafloor has also been excavated. But currently, gold mining from the sea floor and the deep oceanic crust is not considered as efficient mining process.

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Two large, parallel, nonconducting sheets of positive charge face each other. What is at points (a) to the left of the sheets, (

alexira [117]

Answer:

a)The electric Field will be zero at the point between the sheets

b) $E_1=\dfrac{\sigma}{\epsilon_0}$

c) $E_2=\dfrac{\sigma}{\epsilon_0}$

Explanation:

Let $\sigma$ be the surface charge density of the of the non conducting parallel sheet.Let consider a Gaussian surface in the form of of cylinder such that its cross-sectional is A . Then there will be flux only due to cross sectional area as the curved sectional is perpendicular to the the electric field so the Electric Flux due to it is zero.

Now using Gauss law we have, E be the electric Field at the distance r from the sheet then

$E\times 2A=\dfrac{\sigma A}{\epsilon_0}\\E=\dfrac{\sigma}{2\epsilon_0}$

The Field will be away from the sheet and perpendicular to it.

a) The Electric Field between them

$E_1=\dfrac{\sigma}{2\epsilon_0}-\dfrac{\sigma}{2\epsilon_0}\\=0$

b)The Electric Field to the right of the sheets

$E_1=\dfrac{\sigma}{2\epsilon_0}+\dfrac{\sigma}{2\epsilon_0}\\=\dfrac{\sigma}{\epsilon_0}$

c)The Electric Field to the left of the sheets

$E_2=\dfrac{\sigma}{2\epsilon_0}+\dfrac{\sigma}{2\epsilon_0}\\=\dfrac{\sigma}{\epsilon_0}$

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Boiling Point - Higher

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svetoff [14.1K]

D.) In order to calculate both of them, we must know the "FORCE" on the system.

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