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2 years ago

Deposits of gold can be found in the deep ocean. Please select the best answer from the choices provided T F

Physics

2 answers:

Igoryamba2 years ago

7 0

In some cases true, and in others false. but it is true

Setler [38]2 years ago

5 0

Answer: True

The excavation of gold from the deep oceanic vents made possible from the Atlantic and north Pacific oceans. Approximately 100 metric million tons of gold has been excavated from these oceans. Also, the undissolved gold in the seafloor has also been excavated. But currently, gold mining from the sea floor and the deep oceanic crust is not considered as efficient mining process.

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An 18.7 g sample of platinum metal increases

vredina [299]

Answer:

0.092

Explanation:

because i said sooooo

5 0

2 years ago

Which statement is true for a car that first goes around a curve of radius r at a constant speed v, and then goes around the sam

sasho [114]

Centripetal force is equal to (mv^2)/r
The way I use to answer these question is to set every variable to 1
m=1
v=1
r=1
so centripetal force =1
then change the variable we're looking at
and since we're find when it's half we could either change it to 1/2 or 2, but 2 is easier to use
m=1
v=2
r=1
((1)×(2)^2)/1=4
So the velocity in the 1st part is half the velocity in the 2nd part and the centripetal force is 4× less
The answer is the centripetal force is 1/4 as big the second time around

3 0

3 years ago

A car started from a rest and accelerated at 9.54 m/s2 for 6.5 seconds. How much distance was covered by the car?

ElenaW [278]

Explanation:

S =ut + 1/2at^2

S = 0×6.5 + (1/2 × 9.54) × 6.5^2

S =0 + 4.77 ×42.25

S=201.5m

5 0

2 years ago

If a toy car with a coin on top of it is rolling down a hill what force is keeping the coin on top of the car?

forsale [732]

The answer is gravity.

7 0

2 years ago

A Bullet Off mass 100 gm is fired From A Gun Off mass 5 Kg. If the backward velocity of the gun's 5 m / s, what is forward veloc

Elena L [17]

Answer:

250 m/s

Explanation:

The mass of the bullet, m₁ = 100 g = 0.1 kg

The mass of the gun, m₂ = 5 kg

The backward velocity of the gun, v₂ = -5 m/s

Given that the momentum is conserved, we have;

The total initial momentum = The total final momentum

The gun and the bullet are at rest, therefore, we have;

The initial momentum = 0

The total final momentum = m₁·v₁ + m₂·v₂

Where;

v₁ = The forward velocity of the bullet

Therefore, we get;

m₁·v₁ + m₂·v₂ = 0

0.1 kg × v₁ + 5 kg × (-5 m/s) = 0

0.1 kg × v₁ = 5 kg × 5 m/s

v₁ = (5 kg × 5 m/s)/(0.1 kg) = 250 m/s

The forward velocity of the bullet, v₁ = 250 m/s

6 0

2 years ago