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3 years ago

Deposits of gold can be found in the deep ocean. Please select the best answer from the choices provided T F

Physics

2 answers:

Igoryamba3 years ago

7 0

In some cases true, and in others false. but it is true

Setler [38]3 years ago

5 0

Answer: True

The excavation of gold from the deep oceanic vents made possible from the Atlantic and north Pacific oceans. Approximately 100 metric million tons of gold has been excavated from these oceans. Also, the undissolved gold in the seafloor has also been excavated. But currently, gold mining from the sea floor and the deep oceanic crust is not considered as efficient mining process.

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During World War I, the Germans had a gun called Big Bertha that was used to shell Paris. The shell had an initial speed of 1.4

Ksju [112]

Answer:

The shell hit at a horizontal distance 149.41 km

Explanation:

The shell had an initial speed of 1.4 km/s

Initial speed = 1400 m/s

Inclination = 65.8° to the horizontal

First let us find the time of travel

Consider the vertical motion,

We have equation of motion, s = ut + 0.5 at²

Initial velocity, u = 1400 sin 65.8 = 1276.97 m/s

Acceleration, a = -9.81 m/s²

Displacement, s = 0 m

Substituting

s = ut + 0.5 at²

0 = 1276.97 x t + 0.5 x (-9.81) xt²

t = 260.34 s

Now let us find the horizontal displacement,

Consider the horizontal motion,

We have equation of motion, s = ut + 0.5 at²

Initial velocity, u = 1400 cos 65.8 = 573.89 m/s

Acceleration, a = 0 m/s²

Time, t = 260.34 s

Substituting

s = ut + 0.5 at²

s = 573.89 x 260.34 + 0.5 x 0 x 260.34²

s = 149407.11 m = 149.41 km

The shell hit at a horizontal distance 149.41 km

5 0

3 years ago

What is the acceleration of a softball if it hits the ground with a force 0.50 kg and hits the catchers glove with a force of 25

Rom4ik [11]

Acceleration of the ball is $50 m/s^2$

Explanation:

The acceleration of the ball can be found by using Newton's second law of motion, which states that the net force acting on an object is equal to the product between the mass of the object and its acceleration:

$F=ma$

where

F is the net force

m is the mass

a is the acceleration

For the ball in this problem, we have

m = 0.50 kg (mass)

F = 25 N (force)

thereofre, the acceleration of the ball is

$a=\frac{F}{m}=\frac{25}{0.50}=50 m/s^2$

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

5 0

3 years ago

a 1000 kg car crashed into bearer . the car changed speed from 30 m/s to 20 m/s in 2 seconds . What force did the bearer apply t

Allushta [10]

The bearer used an opposite force to slow the car.

3 0

3 years ago

Read 2 more answers

3.00 m3 of a fixed mass of a gas at 150 kPa. Calculate the pressure if the volume is reduced to 1.20 m3 at a constant temperatur

viktelen [127]

Answer:

P₂ = 375 kPa.

Explanation:

Given that,

Initial volume, V₁ = 3 m³

Initial pressure, P₁ = 150 kPa

Final volume, V₂ = 1.2 m³

We need to find the final pressure.

At constant temperature,

$P\propto \dfrac{1}{V}\\\\P_1V_1=P_2V_2\\\\P_2=\dfrac{P_1V_1}{V_2}\\\\P_2=\dfrac{150\ kPa\times 3\ m^3}{1.2\ m^3}\\\\P_2=375\ kPa$

So, the new pressure is 375 kPa.

6 0

3 years ago

If you run east for 38m, stop suddenly, run another 27m east, then you run west for 47

AysviL [449]

Answer:

Total Displacement = -18m

Explanation:

Given

East Movement = 38m and 27m

West Movement = 47m

Required

Determine the total displacement

To answer this, we consider east as negative direction and the west as positive (using logics of number line).

Total Displacement = East Movement + West Movement

Total Displacement = -38m - 27m + 47m

Total Displacement = -18m

Hence, the total displacement is 18m towards East

6 0

3 years ago