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irga5000 [103]
4 years ago
15

Which statement regarding the Calvin cycle is false?

Chemistry
1 answer:
scoundrel [369]4 years ago
3 0

Answer:

The statement "Six turns of the cycle are required for every glucose molecule later produced in non–Calvin cycle reactions" is incorrect.  It really looks not well-worded.

Explanation:

It is incorrect because Six turns of the cycle are required for every glucose molecule produced in Calvin cycle reactions, no in non-Calvin cycle reactions.  This process includes the fixation of 6 molecules of carbon dioxide to produce 1 Glucose (seen as the addition of the two Phosphoglyceraldehide molecules (PGAL).  Moreover, the other statements in the questions are correct:

ATP is required during carbon fixation.

The most intensive energy phase is reduction and sugar production.

Twelve NADPH are required for every six CO2 fixed.

NADPH is required for reduction and sugar production.

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4 0
3 years ago
A piece of fossilized wood has a carbon-14 radioactivity that is 1/4 that of new wood. the half-life of carbon-14 is 5730 years.
Marizza181 [45]

Answer:

1.146 x 10⁴ year.

Explanation:

  • The decay of carbon-14 is a first order reaction.
  • The rate constant of the reaction (k) in a first order reaction = ln (2)/half-life = 0.693/(5730 year) = 1.21 x 10⁻⁴ year⁻¹.
  • The integration law of a first order reaction is:

<em>kt = ln [A₀]/[A]</em>

<em></em>

k is the rate constant = 1.21 x 10⁻⁴ year⁻¹.

t is the time = ??? years.

[A₀] is the initial percentage of carbon-14 = 100.0 %.

[A] is the remaining percentage of carbon-14 = 1/4[A₀] = 25.0 %.

∵ kt = ln [Ao]/[A]

∴ (1.21 x 10⁻⁴ year⁻¹)(t) = ln (100.0%)/[25.0 %]

(1.21 x 10⁻⁴ year⁻¹)(t) = 1.386.

∴ <em>t </em>= 1.386/ (1.21 x 10⁻⁴ year⁻¹) =  <em>1.146 x 10⁴ year.</em>

3 0
4 years ago
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