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3 years ago

What type of organic molecule comprises the majority of a potato?

Chemistry

1 answer:

vladimir1956 [14]3 years ago

8 0

Your answer should be Polysaccharides

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______ break down sugars to produce energy.

Mariana [72]

Answer:

mitochondria

Explanation:

I took the test

8 0

2 years ago

Why do oxygen and hydrogen connect (attach) underwater?

Usimov [2.4K]

The slight positive charges on the hydrogen atoms in water molecules attract the slight negative charges on the oxygen atoms of the other water molecules

7 0

3 years ago

a solution of sodium hydroxide, 0.0500 M, is used to titrate a 15.00 mL sample of hydrochloric acid to the endpoint. The initial

Akimi4 [234]

Answer:

The answer to your question is Molarity = 0.0708

Explanation:

Data

NaOH 0.05 M Volume 1 = 3.87 ml Volume 2 = 25.11 ml

HCl 15 ml

Process

1.- Find the volume used of NaOH

25.11 - 3.87 = 21.24 ml = 0.02124 l

2.- Write the balanced equation of the reaction

NaOH + HCl ⇒ NaCl + H₂O

3.- Calculate the moles of NaOH in the solution

Molarity = $\frac{moles}{volume}$

moles = Molarity x volume

moles = 0.05 x 0.02124

moles = 0.001062

4.- From the reaction we know that NaOH and HCl react in a proportion 1:1.

1 mol of NaOH ------------- 1 mol of HCl

0.001062 moles of NaOH ------------ x

x = (0.001062 x 1) / 1

x = 0.001062 moles of HCl

5.- Find the molarity of HCl

Molarity = $\frac{0.001062}{0.015}$

Molarity = 0.0708

4 0

3 years ago

Balance the following redox equation and identify the element oxidized, the element reduced, the oxidizing agent, and the reduci

earnstyle [38]

The charge of Br changed from –1 to 0, therefore it is the element which is oxidized. Since it is oxidized then Br is also the reducing agent.

The charge of Mn changed from +4 to +2 therefore it is the element which is reduced. Since Mn is reduced, then MnO2 is the oxidizing agent.

The half –reactions are:

Br: 2Br --> Br2 + 2e-

Mn: MnO2 --> Mn2+

First balance oxygen by adding H2O:

MnO2 --> Mn2+ + 2H2O

Then balance hydrogen by adding H+ ions:

4H+ + MnO2 --> Mn2 + 2H2O

Then the appropriate electrons:

4e- + 4H+ + MnO2 --> Mn2 + 2H2O

Multiply the half-reaction of Br by 2 because the half-reaction of Mn has 4 electrons.

4Br --> 2Br2 + 4e-

Combine the two half reactions and cancel common factors:

4Br- + 4H+ + MnO2 --> 2Br2 + Mn2 + 2H2O

6 0

2 years ago

NEED HELP ASAP!!! What is the density of each of the following gases at STP? Show your work.

BaLLatris [955]

Answer:

A. 1.63g/dm^3 (3 s.f.)

B. 0.833g/dm^3 (3 s.f.)

C. 1.92g/dm^3 (3 s.f.)

Explanation:

Please see attached picture for full solution.

3 0

3 years ago