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suter [353]
3 years ago
13

Describe the reactions during the electrolysis of water in an electrolytic cell. Group of answer choices Oxygen and hydrogen are

both oxidized. Oxygen is oxidized and hydrogen is reduced. Oxygen is reduced and hydrogen is oxidized. Oxygen and hydrogen are both reduced. Neither oxygen or hydrogen are oxidized or reduced.
Chemistry
1 answer:
Ann [662]3 years ago
6 0

Answer:

Oxygen is oxidized and hydrogen is reduced.

Explanation:

Let's consider the redox reaction during the electrolysis of water in an electrolytic cell.

2 H₂O ⇒ 2 H₂ + O₂

The corresponding half-reactions are:

2 e⁻ + 2 H₂O ⇒ H₂ + 2 OH⁻

2 H₂O ⇒ O₂ + 4 H⁺ + 4 e⁻

Oxygen is oxidized since its oxidation number increases from -2 to 0.

Hydrogen is reduced since its oxidation number decreases from +1 to 0.

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mr Goodwill [35]
C3H8+3O2--->3CO2+8H
Therefore for every 1:3 there are 3 Carbon dioxides that form. That means find the limiting reactant from the two reactants.
5.5g(1mole C3H8/44.03g of C3H8)=0.1249 moled of C3H8 and if for every one C3H8 we can form three CO2. We can assume 0.3747 miles of CO2 will be produced.
15g of O2(1 mole O2/32g of O2)=0.4685moles O2 and if for every three O2 we can produce three CO2 we may assume a 1:1 ratio.
This means C3H8 will be your limiting reactant. Therefore 0.3747 moles of CO2 will be produced.
0.3747 moles of CO2(48.01 g of CO2/1 mole of CO2)= 17.99 grams of CO2
5 0
3 years ago
A sealed can of your favorite soda has a carbon dioxide gas (C0) volume of 0.05 L. When it is refrigerated, the
liubo4ka [24]

Answer:

<h2>0.102 L</h2>

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question we have

V_2 =  \frac{207000 \times 0.05}{101000}  =  \frac{10350}{101000}  \\  = 0.102475...

We have the final answer as

<h3>0.102 L</h3>

Hope this helps you

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MissTica
Answer:


False
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