Answer:
group 17 the halogen.as it has 7 electron in its outermost ring
There are 5.01 × 10-⁷grams in 4.07 x 10¹⁵molecules of calcium hydroxide.
HOW TO CALCULATE MASS:
The mass of a substance can be calculated by multiplying the number of moles in the substance by its molecular mass.
However, given that the number of molecules in calcium hydroxide is 4.07 x 10¹⁵molecules, we need to calculate the number of moles in Ca(OH)2 as follows:
no. of moles of Ca(OH)2 = 4.07 x 10¹⁵ ÷ 6.02 × 10²³
no. of moles = 0.676 × 10-⁸
no. of moles = 6.76 × 10-⁹ moles.
Molar mass of Ca(OH)2 = 74.093 g/mol
Mass of Ca(OH)2 = 74.093 × 6.76 × 10-⁹ moles
Mass = 5.01 × 10-⁷grams.
Therefore, there are 5.01 × 10-⁷grams in 4.07 x 10¹⁵molecules of calcium hydroxide.
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Answer:
The final concentration is 0,151 M.
Explanation:
A dilution consists of the decrease of concentration of a substance in a solution (the higher the volume of the solvent, the lower the concentration).
We convert the unit of volume in L into ml: 3,25 x 1000= 3250 ml
We use the formula for dilutions:
C1 x V1 = C2 x V2
C2= (C1 xV1)/V2
C2= (32, 5 ml x 15, 1 M)/ 3250 ml
<em>C2=0,151 M</em>
In order for you to get the answer, please have in mind the following situation: To increase the molar concentration of N2O4(g), 2NO2(g) should also increase for equilibrium to occur. Now, this equation is exothermic. By <span>Le Chatelier's principle, equilibrium constant and reaction constants also come into play in terms of increasing or decreasing the temperature. After that I know you can find the answer. </span>