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suter [353]
3 years ago
13

Describe the reactions during the electrolysis of water in an electrolytic cell. Group of answer choices Oxygen and hydrogen are

both oxidized. Oxygen is oxidized and hydrogen is reduced. Oxygen is reduced and hydrogen is oxidized. Oxygen and hydrogen are both reduced. Neither oxygen or hydrogen are oxidized or reduced.
Chemistry
1 answer:
Ann [662]3 years ago
6 0

Answer:

Oxygen is oxidized and hydrogen is reduced.

Explanation:

Let's consider the redox reaction during the electrolysis of water in an electrolytic cell.

2 H₂O ⇒ 2 H₂ + O₂

The corresponding half-reactions are:

2 e⁻ + 2 H₂O ⇒ H₂ + 2 OH⁻

2 H₂O ⇒ O₂ + 4 H⁺ + 4 e⁻

Oxygen is oxidized since its oxidation number increases from -2 to 0.

Hydrogen is reduced since its oxidation number decreases from +1 to 0.

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An undergraduate weighed out 20grams of sodium hydroxide pellets. If Na =23, O = 16 andH = 1, What is the mole of this sodium hy
tatuchka [14]
The answer would be .5 mols because you take the total amount of grams, which is 20, and you had up the molar mass of sodium hydroxide, which would be 40. After you have this you would set this up as a stochiometry equation. With 1 mol on top you dived 20/40 to cancel out your grams. This leaves you with .5 mols

3 0
4 years ago
Which of the following sequences of elements would all have four valence electrons?
timama [110]

Answer:b

Explanation:

8 0
3 years ago
What are the 2 products of photosynthesis
makkiz [27]
Carbon dioxide and oxygen
7 0
3 years ago
What volume would 56.2 mL of gas at 820 mm of Hg occupy at 720 mm of Hg?
Andreyy89

Answer:

49.35  mL

Explanation:

Given: 56.2 mL of gas

To find: volume that 56.2 mL of gas at 820 mm of Hg would occupy at 720 mm of Hg

Solution:

At 820 mm of Hg, volume of gas is 56.2 mL

At 1 mm of Hg, volume of gas is \frac{56.2}{820}

At 720 mm of Hg, volume of gas is \frac{56.2}{820}(720)=49.35\,\,mL

3 0
3 years ago
Which of the following is most likely to form multiple (double or triple) bonds? 1. Li 2. Cl 3. N 4. H 5. F
alukav5142 [94]

Answer: Option (3) is the correct answer.

Explanation:

Atomic number of lithium is 3 and its electronic distribution is 2, 1. So, to attain stability it will loose an electron and hence, it forms a single bond.

Atomic number of chlorine is 17 and it has 7 valence electrons. Hence, in order to attain stability it will gain one electron and therefore, it forms a single bond only.

Atomic number of nitrogen is 7 and its electronic distribution is 2, 5. Therefore, to attain stability it needs to gain 3 more electrons. Hence, a nitrogen atom is able to form a triple bond and also it is able to form a double bond.

Hydrogen has atomic number 1 and it attains stability by gaining one electron. Therefore, a hydrogen atoms always forms a single bond.

Atomic number of fluorine is 9 and its electronic distribution is 2, 7. To complete its octet it needs to gain one electron. Hence, a fluorine atom always forms a single bond.

Thus, we can conclude that out of the given options nitrogen is most likely to form multiple (double or triple) bonds.

3 0
3 years ago
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