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dimaraw [331]
3 years ago
9

Suppose that 17 inches of wire costs 51 cents.

Mathematics
1 answer:
Nataliya [291]3 years ago
4 0

Answer:

$0.39

Step-by-step explanation:

51/17 = 3

$0.03 per inch

0.03 × 13 = 0.39

$0.39

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Then each week thereafter, you add $5 to the account but no interest is earned. Suppose you receive $100 for a graduation presen
irga5000 [103]
100 + 5x = y

100 +5x = 310
x = 42 weeks

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3 years ago
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Find the indicated side of the<br> triangle.<br> b<br> 7<br> 45°<br> a<br> b = [?]VO
vodka [1.7K]

Answer:

7√2

Step-by-step explanation:

Thank to the give angle we can say that the two legs are congruent

b = \sqrt{7^2 + 7^2} = \sqrt{49+49} = \sqrt{98}

98/2 = 49

49/7 = 7

7/7 = 1

98 = 7^2 x 2

√98 = 7√2

8 0
3 years ago
Let <img src="https://tex.z-dn.net/?f=i" id="TexFormula1" title="i" alt="i" align="absmiddle" class="latex-formula"> be the imag
VLD [36.1K]

Hey~freckledspots!\\----------------------

We~will~solve~for~i^{425}!

Rule~of~exponent: a^{b + c} = a^ba^c\\Apply:~i^{425}~=~i^{424}i\\ \\Rule~of~exponent: a^{bc} = (a^{b})^c\\Apply: i^{424} = i(i^2)^{212} \\\\Rule~of~imaginary~number: i^2 = -1\\Apply: i(i^2)^{212} = -1^{212}i\\\\Rule~of~exponent~if~n~is~even: -a^n = a^n\\Apply: -1^{212}i = 1^{212}i\\\\Simplify: 1^{212}i = 1i\\Multiply: 1i * 1 = i\\----------------------\\

Now~let's~solve~1^{14}!\\\\Rule~of~exponent: a^{b + c} = a^ba^c\\Apply: i^{14} = (i^2)^7\\\\Rule~of~imaginary~number: i^2 = -1\\Apply: (i^2)^7 = -1^7\\\\Rule~of~exponent~if~n~is~odd: (-a)^n = -a^n\\Apply: -1^7 = -1^7\\\\Simplify: -1^7 = -1\\----------------------\\Now,~we~have: i-1+i^{-14}+i^{44}\\----------------------

Now~lets~solve~i^{-14}\\\\Rule~of~exponent: a^{-b} = \frac{1}{a^b} \\Apply: i^{-14} = \frac{1}{i^{14}} \\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: \frac{1}{i^{14}} = \frac{1}{(i^2)^7}\\ \\Rule~of~imagianry~number: i^2 = -1\\Apply: \frac{1}{(i^2)^7} = \frac{1}{-1^7} \\\\Simplify: \frac{1}{-1^7} = \frac{1}{-1} \\\\Rule~of~fractions: \frac{a}{-b} = -\frac{a}{b} \\Apply: \frac{1}{-1} = -\frac{1}{1} = -1\\----------------------\\Now,~we~have: i-1-1+i^44\\----------------------

Now~let's~solve~i^{44}!\\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: i^{44} = (i^2)^{22}\\\\Rule~of~imaginary~numbers: i^2 = -1\\Apply: (i^2)^{22} = -1^{22}\\\\Rule~of~exponent~if~n~is~even: (-a)^n = a^n\\Apply: -1^{22} = 1^{22}\\\\Simplify: 1^{22} = 1\\----------------------\\Now,~we~have~i-1-1+1\\----------------------

Now~let's~simplify~the~expression!\\\\= i-1-1+1 \\= 1 + i -2\\= -1+i\\----------------------

Answer:\\\large\boxed{-1+i}\\----------------------

Hope~This~Helped!~Good~Luck!

8 0
4 years ago
Read 2 more answers
Please help with this
lana66690 [7]
Alright, let's convert to decimals for these calculations: fractions could get messy.
1/5 = .2
1/2 = .5

Imagine a rectangular solid in your mind. How many sides does it have?
6. In the image shown you have 3 facing you. In addition to those, there are 3 not shown. They will correspond to the calculations you make on the front, though, so all you have to do is double the values you get.

Area is length * width, or length * height, or width * height. So:
A = 3.2 (length) * 4.5 (height) for the front face of the rectangular solid(as well as the back face.)
A = 5 (width) * 4.5 (height) for the right face of the rectangular solid (and the one on the left, away from you.)
A = 3.2 (length) * 5 (width) for the top of the solid(and the bottom).

Calculating these values, we get that 
A=14.4
A=22.5
A= 16
So that's 3 out of 6 values for the full surface area.
Like I said though, these values can merely be doubled for the complete area.
Add these three together:
14.4+22.5+16=52.9
multiply by 2 to account for the other 3 sides
52.9 * 2 = 105.8
105.8 is the surface area.
4 0
3 years ago
Solve the following inequality for s. Write your answer in simplest form.
Doss [256]

\qquad\qquad\huge\underline{{\sf Answer}}♨

Let's solve ~

\qquad \sf  \dashrightarrow \: - 10 + 5(78 + 8) <  - 4s + 3 - 8

\qquad \sf  \dashrightarrow \: - 10 + 5(86) <  - 4s  - 5

\qquad \sf  \dashrightarrow \: - 10 +430 <  - 4s  - 5

\qquad \sf  \dashrightarrow \: 420 + 5 <  - 4s

\qquad \sf  \dashrightarrow \: 42 5 <  - 4s

\qquad \sf  \dashrightarrow \: 42 5 \div 4 <   - s

\qquad \sf  \dashrightarrow \: 106.25 <   - s

Inequalities change when it is multiplied by -ve number

\qquad \sf  \dashrightarrow \:  - 106.25  >    s

3 0
2 years ago
Read 2 more answers
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