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-BARSIC- [3]
2 years ago
15

In reaching her destination, a backpacker walks with an average velocity of 1.32 m/s, due west. This average velocity results, b

ecause she hikes for 5.21 km with an average velocity of 3.49 m/s due west, turns around, and hikes with an average velocity of 0.687 m/s due east. How far east did she walk (in kilometers)?
Physics
1 answer:
Svetach [21]2 years ago
8 0

Answer:

distance in east is 1273.78 m

Explanation:

given data

average velocity = 1.32 m/s west =

hike = 5.21 km = 5.21 × 10³ m

average velocity = 3.49 m/s west

average velocity = 0.687 m/s east

to find out

distance in east

solution

we consider here distance in east  is = x

so distance from starting point = 5.21 × 10³ - x        ...................1

and we can say time required to reach end

time required = distance / speed

time required = \frac{5.21 *10^3 - x}{1.32}    ................2

and

time required for 6.44 km west

time required = \frac{5.21 *10^3 - x}{3.49}    ................3

and time required for distance x

time required = \frac{x}{0.687}    ................4

so from equation 2 , 3 and 4

\frac{5.21 *10^3 - x}{1.32} = \frac{5.21 *10^3 - x}{3.49}  + \frac{x}{0.687}

x = 1273.78 m

so distance in east is 1273.78 m

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After the great 1906 San Francisco earthquake, geolophysicistHarry Fielding Reid examined the displacement of the ground surface along the San Andreas Fault. He concluded that the quake must have been the result of the elastic reboundof the strain energy in the rocks on either side of the fault.
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7 0
3 years ago
Write the realtionship between the density of a liquid and its upthrust? clarify​
kipiarov [429]

Answer:

B = ρ g V_liquid

the thrust is proportional to the density of the liquid

Explanation:

The density of a liquid is defined as the relationship between the mass and the volume of the liquid

         ρ = m / V

The upward push of the liquid is given by the principle of Archimedes Archimedes establishes that the push is equal to the weight of the dislodged liquid

        B = W_liquid

        B = m _liquid g

we substitute mass for density

        B = ρ g V_liquid

therefore we see that the thrust is proportional to the density of the liquid

8 0
2 years ago
In Part 6.2.2, you will determine the wavelength of the laser by shining the laser beam on a "diffraction grating", a set of reg
harkovskaia [24]

Answer:

λ = 2042 nm

Explanation:

given data

screen distance d = 11 m

spot s = 4.5 cm = 4.5 ×10^{-2} m

separation L = 0.5 mm = 0.5 ×10^{-3} m

to find out

what is λ

solution

we will find first angle between first max and central bright

that is tan θ = s/d

tan θ = 4.5 ×10^{-2}  / 11

θ = 0.234

and we know diffraction grating for max

L sinθ  = mλ

here we know m = 1  so put all value and find λ

L sinθ  = mλ

0.5 ×10^{-3}  sin(0.234)  = 1 λ

λ = 2042.02 ×10^{-9}  m

λ = 2042 nm

3 0
3 years ago
Which of the following is not a colligative property? a. osmotic pressure b. lattice energy c. vapor-pressure lowering d. boilin
Gre4nikov [31]

Answer:

b) lattice energy

Explanation:

A solution is said to have colligative property when the property depends on the solute present in the solution.

Colligative property depend upon on the solute particle or the ion concentration not on the identity of solute.

osmotic pressure, vapor pressure lowering , boiling point elevation and freezing point lowering all depend upon solute concentration so they will not have colligative property so, the answer remains option 'b' which is lattice energy.

8 0
3 years ago
A boat heads due North for 3.00 km to reach a red buoy. It then changes direction and heads in a direction of 30.0 degrees South
Helga [31]

Position of B :  

x = 4.66*cos 30 = 4.036  

y = 3-4.66*sin 30 = 3-2.33 = 0.67  

BC = √y^2+(x-1)^2 = √0.67^2+3.036^2 = 3.109  

heading = arctan y/(x-1) = arctan 0.67/(3.036) = 12.44° south of west

hope this helps :)

6 0
3 years ago
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