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3 years ago

15

In reaching her destination, a backpacker walks with an average velocity of 1.32 m/s, due west. This average velocity results, b

ecause she hikes for 5.21 km with an average velocity of 3.49 m/s due west, turns around, and hikes with an average velocity of 0.687 m/s due east. How far east did she walk (in kilometers)?

1 answer:

Svetach [21]3 years ago

8 0

Answer:

distance in east is 1273.78 m

Explanation:

given data

average velocity = 1.32 m/s west =

hike = 5.21 km = 5.21 × 10³ m

average velocity = 3.49 m/s west

average velocity = 0.687 m/s east

to find out

distance in east

solution

we consider here distance in east is = x

so distance from starting point = 5.21 × 10³ - x ...................1

and we can say time required to reach end

time required = distance / speed

time required = $\frac{5.21 *10^3 - x}{1.32}$ ................2

and

time required for 6.44 km west

time required = $\frac{5.21 *10^3 - x}{3.49}$ ................3

and time required for distance x

time required = $\frac{x}{0.687}$ ................4

so from equation 2 , 3 and 4

$\frac{5.21 *10^3 - x}{1.32}$ = $\frac{5.21 *10^3 - x}{3.49}$ + $\frac{x}{0.687}$

x = 1273.78 m

so distance in east is 1273.78 m

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