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3 years ago

10

Choose a sport or sporting play. Describe the types of energy involved in playing the sport. State whether playing the sport is

an energy transfer or energy transformation

1 answer:

Wittaler [7]3 years ago

8 0

I’m epic $$$$$$$$$777$$777$$$$$77777777$$

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How do I do molarity equations?

ipn [44]

To calculate the molarity of a solution, you divide the moles of solute by the volume of the solution expressed in liters. Note that the volume is in liters of solution and not liters of solvent. When a molarity is reported, the unit is the symbol M and is read as “molar”.
I hope this helped :)
Please make me the branliest! Have a good night/ good day!!

8 0

2 years ago

"You have a solution of glucose in water that has a concentration of 2.50 M and a volume of 0.442 liters. You dilute this soluti

taurus [48]

Answer:

0.737M

Explanation:

C1V1=C2V2

2.50 x 0.442 = C x 1.5

1.105 = C x 1.5

C = 1.105/1.5

C = 0.737M

7 0

2 years ago

Help Asap!! I will try to mark Brainliest!✨

lbvjy [14]

If I remember correctly from my science class, it is Protons and Neutrons.

Hope this helps, if not, comment below please!!!

7 0

2 years ago

Read 2 more answers

Nitrogen monoxide, NO, reacts with hydrogen, H₂, according to the following equation.

Anvisha [2.4K]

Answer : The rate law for the overall reaction is, $Rate=k[NO]^2[H_2]$

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

As we are given the mechanism for the reaction :

Step 1 : $2NO+H_2\rightarrow N_2+H_2O_2$ (slow)

Step 2 : $H_2O_2+H_2\rightarrow 2H_2O$ (fast)

Overall reaction : $2NO+2H_2\rightarrow N_2+2H_2O$

The rate law expression for overall reaction should be in terms of $NO\text{ and }H_2$ .

As we know that the slow step is the rate determining step. So,

The slow step reaction is,

$2NO+H_2\rightarrow N_2+H_2O_2$

The expression of rate law for this reaction will be,

$Rate=k[NO]^2[H_2]$

Hence, the rate law for the overall reaction is, $Rate=k[NO]^2[H_2]$

8 0

3 years ago

Many oxidation-reduction reactions can be balanced by inspection. Try to balance the following reactions by inspection. In each

Phoenix [80]

Answer:

Balanced reaction: C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

Reduced: O₂

Oxidized : C₃H₈

Explanation:

For the given reaction:

C₃H₈(g) + O₂(g) → CO₂(g) + H₂O(l)

In the reactants, there are 3 C, and in the products only one, so we multiply CO₂ by 3:

C₃H₈(g) + O₂(g) → 3CO₂(g) + H₂O(l)

In the reactants, there are 8 H, and in the products, there are 2 H, so we multiply H₂O by 4:

C₃H₈(g) + O₂(g) → 3CO₂(g) + 4H₂O(l)

In the reactants are 2 O, and in the products 10 O, so we multiply O₂ by 5:

C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

The reaction is balanced.

Let's identify the oxidation number (Nox) of the elements in each compound.

C₃H₈:

H has fix Nox equal to +1, and the molecule is neutral, so, calling x the Nox of C:

3x + 8 = 0

3x = -8

x = -8/3

O₂:

Because is a pure compound, the Nox of O is 0.

CO₂:

The Nox of O is fix equal to -2, and the molecule is neutral, so, calling x the Nox of C:

2x -4 = 0

2x = 4

x = +2

H₂O:

The Nox of H and O are fixed, respectively, +1 and -2.

So, the carbon in C₃H₈ is oxidized because its Nox is increasing, and oxygen in O₂ is reduced because its Nox is decreasing.

6 0

3 years ago