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Romashka [77]
3 years ago
10

Explain HOW this chemical reaction is NOT balanced correctly.

Chemistry
2 answers:
KatRina [158]3 years ago
6 0

Explanation:

On the reactant side,

*the atomicity of silicon in silicon flouride(SiF4) is 1

*the atomicity of flourine in SiF4 is 4

*the atomicity of hydrogen in two molecules of water is 4

*the atomicity of oxygen in two molecules of water is 2

On the product side,

*the atomicity of hydrogen in orthosilicic acid(H4SiO4) + atomicity of hydrogen in hexaflourosilic acid =8

*the atomicity of silicon in H4SiO4 + atomicity of silicon in 2H2SiF6 =3

*the atomicity of oxygen in H4SIO4 is 4

*the atomicity of flourine in 2H2SIF6 is 12

RS. PS

Si= 1. 3

H= 4. 8

O= 2. 4

F= 4. 12

The correct EQ is ;

3SiF4 + 4H2O ------>H4SIO4 + 2H2SiF6

NeTakaya3 years ago
5 0

Answer: there is more atoms of each element on the right.

Explanation:

On the left of the arrow you have:

Si-1

F-4

H-4

O-2

On the right of the arrow you have:

Si-3

F-6

H-8

O-4

A balanced equation always has the same amount of each element on the left of the arrow (the reactants) as the right (the products). This isn’t balanced because you have a lot more of each element on the right.

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Mass of water 50.003 g 24 95C Temperature of water Specific heat capacity for water 4.184J/g C Mass of metal 3.546 Temperature o
Norma-Jean [14]

Correct Question :

Mass of water = 50.003g

Temperature of water= 24.95C

Specific heat capacity for water = 4.184J/g C

Mass of metal = 63.546 g

Temperature of metal 99.95°C

Specific heat capacity for metal ?

Final temperature = 32.80°C

In an experiment to determine the specific heat of a metal student transferred a sample of the metal that was heated in boiling water into room temperature water in an insulated cup. The student recorded the temperature of the water after thermal equilibrium was reached. The data we shown in the table above. Based on the data, what is the calculated heat absorbed by the water reported with the appropriate number of significant figures?

Answer:

1642 J

Explanation:

Given:

Mass of water = 50.003g

Temperature of water= 24.95C

Specific heat capacity for water = 4.184J/g C

Mass of metal = 63.546 g

Temperature of metal 99.95°C

Specific heat capacity for metal ?

Final temperature = 32.80° C

To calculate the heat absorbed by water, Q, let's use the formula :

Q = ∆T * mass of water * specific heat

Where ∆T = 32.80°C - 24.95°C = 7.85°C

Therefore,

Q= 7.85 * 50.003 * 4.184

Q = 1642.32 J

≈ 1642 J

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Answer:

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