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Romashka [77]
3 years ago
10

Explain HOW this chemical reaction is NOT balanced correctly.

Chemistry
2 answers:
KatRina [158]3 years ago
6 0

Explanation:

On the reactant side,

*the atomicity of silicon in silicon flouride(SiF4) is 1

*the atomicity of flourine in SiF4 is 4

*the atomicity of hydrogen in two molecules of water is 4

*the atomicity of oxygen in two molecules of water is 2

On the product side,

*the atomicity of hydrogen in orthosilicic acid(H4SiO4) + atomicity of hydrogen in hexaflourosilic acid =8

*the atomicity of silicon in H4SiO4 + atomicity of silicon in 2H2SiF6 =3

*the atomicity of oxygen in H4SIO4 is 4

*the atomicity of flourine in 2H2SIF6 is 12

RS. PS

Si= 1. 3

H= 4. 8

O= 2. 4

F= 4. 12

The correct EQ is ;

3SiF4 + 4H2O ------>H4SIO4 + 2H2SiF6

NeTakaya3 years ago
5 0

Answer: there is more atoms of each element on the right.

Explanation:

On the left of the arrow you have:

Si-1

F-4

H-4

O-2

On the right of the arrow you have:

Si-3

F-6

H-8

O-4

A balanced equation always has the same amount of each element on the left of the arrow (the reactants) as the right (the products). This isn’t balanced because you have a lot more of each element on the right.

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Answer:

Increase

Explanation:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

If the initial temperature and pressure is standard,

Pressure = 1 atm

Temperature = 273.15 K

then we increase the temperature to 400.0 K, The pressure will be,

1 atm / 273.15 K = P₂/400.0K

P₂ = 1 atm × 400.0 K / 273.15 K

P₂ = 400.0 atm. K /273.15 K

P₂ = 1.46 atm

Pressure is also increase from 1 atm to 1.46 atm.

8 0
3 years ago
What percentage of strontium-90 remains in a sample after three half-lives have passed? 12.5% 15% 25% 60%?
Lyrx [107]

12.5% of strontium-90 would remain in a sample after three half-lives have passed. Half-life automatically means 50% of the original amount would remain.

4 0
3 years ago
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scZoUnD [109]
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8 0
4 years ago
How many kilojoules of heat are absorbed when 2.00 L of water is heated from 19*C to 80*C? (Show all work including the equation
Snowcat [4.5K]

Answer:

The answer to your question is 510.7 kJ

Explanation:

Data

Q = ?

Volume = 2 L

Temperature 1 = T1 = 19°C

Temperature 2 = T2 = 80°C

Specific heat = 4.186 J/kg°C

Density of water = 1 g/ml

Equation

              Q = mC(T2 - T1)

Process

1.- Calculate the mass of water

mass = density x volume

mass = 1 x 2000

mass = 2000 g

2.- Substitute values in the Heat formula

              Q = (2000)(4.186)(80 - 19)

-Simplification

               Q = (2000)(4.186)(61)

-Result

              Q = 510692 J  or 510.7 kJ

7 0
4 years ago
I need answers plz<br>btw D says ice crystals ​
tangare [24]

Answer:

B. Hydrogen and oxygen molecules

General Formulas and Concepts:

<u>Chemistry - Reactions</u>

  • Reactants are always on the left side of the arrow
  • Products are always on the right side of the arrow

Explanation:

<u>Step 1: Define</u>

Reaction RxN:   2H₂ + O₂ → 2H₂O

<u>Step 2: Identify</u>

Reactants:   H₂ and O₂

Products: H₂O

7 0
3 years ago
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