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Galina-37 [17]
3 years ago
11

The molecule of ethane posses which hybridization..........

Chemistry
1 answer:
LiRa [457]3 years ago
5 0

Answer:

Sp3

Explanation:

Hydrocarbon can be defined as an organic compound that comprises of hydrogen and carbon only. Some examples of hydrocarbon are methane, butane, ethane, ethene, etc.

Hybridization can be defined as a phenomenon which involves the combination of two or more atomic orbitals to form the same number of hybrid orbitals, with each of the orbitals having the same shape and energy.

In Organic chemistry, ethane is considered to be a tetrahedral carbon and it's Sp3 hybridized.

A tetrahedral carbon typically comprises of four bonds that are 109. 5° apart while a linear carbon atom comprises of two (2) bonds that are 180° apart.

Hence, the molecule of ethane posses a Sp3 hybridization because it has four bonds arrange with a tetrahedral geometry.

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Calculate the % composition of the unknown liquid using your most precise result. It is a mixture of ethanol (D[ETOH] = 0.7890 g
Rufina [12.5K]

% composition of ethanol = 34.51%

% composition of water  = 65.49%

<h3>What is density?</h3>

A material's density is defined as its mass per unit volume.

Given data:

The density of ethanol = 0.7890 g/mL

The density of water = 0.9982 g/mL

The density of mixture = 0.926 g/mL

Let the % composition of ethanol = x

Let the % composition of water = 100-x

Now density of the mixture

\frac{Mass}{Volume}

Mass = \frac{percent  \;of  \;ethanol  \;X  \;density  \;of  \;ethanol  \;+  \\ \;percent  \;of  \;water X  \;density  \;of  \;water}{100}

0.926 = \frac{x X  0.7890 g/mL  \;+  (100-x) X  0.9982 g/mL}{100}

x= 34.51 %

Hence,

% composition of ethanol = 34.51%

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Learn more about the density here:

brainly.com/question/952755

#SPJ1

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