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Anastaziya [24]
3 years ago
8

How many neutrons does an element have of its atomic number is 50 and its mass number is 156?

Physics
1 answer:
pshichka [43]3 years ago
3 0

Ok so I think you would first subtract


156 - 50 = 106


Since atomic number is based on the number of protons, you should subtract the 50 from 156


106 should be your answer


Hope this helps!

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A magnetic B field of strength 0.9 T is perpendicular to a loop with an area of 3 m2. If the area of the loop is reduced to zero
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Answer:

The magnitude of induced emf is 5.4 V

Explanation:

Given:

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Area of loop \Delta A = 3 m^{2}

Time take to reduce loop to zero \Delta t = 0.5 sec

To find induced emf we use faraday's law,

Induced emf is given by,

  \epsilon = -\frac{\Delta \phi}{\Delta t}

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Where \phi = B\Delta A

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   \epsilon = \frac{B\Delta A}{\Delta t}

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Answer:

The arrow will hit 112.07 m from the point of release.

Explanation:

The equation for the position of an object in a parabolic movement is as follows:

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Where:

x0 = initial horizontal position

v0 = initial velocity

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y0 = initial vertical position

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g = acceleration due to gravity

We know that at the final time the y-component of the vector "r" (see figure") is -1.88 m. The x-component of that vector will be the horizontal distance traveled by the arrow. Using the equation of the y-component of "r", we can obtain the final time and with that time we can calculate the value of the x-component (horizontal distance).

Then:

y = y0 + v0 · t · sin α + 1/2 · g · t²

Since the origin of the frame of reference is located at the point where the arrow is released, y0 = 0. Notice that the angle α = 26° + 15° = 41° ( see figure)

-1.88 m = 33 m/s · sin 41° · t - 1/2 · 9.8 m/s² · t²    (g is downward)

0 = -4.9 m/s² · t² + 33 m/s · sin 41° · t + 1.88 m

Solving the quadratic equation:

t = 4.5 s   ( the negative value is discarded)

Now, with this time we can calculate the horizontal distance:

x = x0 + v0 · t · cos α    (x0 = 0, the same as y0)

x = 33 m/s · 4.5 s · cos 41° = 112.07 m

6 0
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