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exis [7]
1 year ago
14

Assume that the ammeter in the figure below is removed and the current that flows through the 4.0Ω path, I3, is unknown. Determi

ne all the currents in the circuit.

Physics
1 answer:
qaws [65]1 year ago
8 0

The circuit is in parallel connection

Equivalent resistance = 1/Req = 1/R1 + 1/R2 + 1/R3

From the information given,

R1 = 5

R2 = 2

R3 = 4

1/Req = 1/5 + 1/2 + 1/4 = (4 + 10 + 5)/20 = 19/20

Req = 20/19 = 1.053 ohms

I = V/R

Given that V = 12,

Current flow through circuit = 12/1.053 = 11.4 A

I1 + I2 + I3 = 11.4

I1 = 12/5 = 2.4 A

I2 = 12/2 = 6 A

I3 = 12/4 = 3A

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3 years ago
Three resistors of equal resistance are connected in series as shown. Compared to the voltage provided by the battery, voltage a
dsp73

Answer:

the voltage across each resistor is one third of the battery voltage

Explanation:

In a series circuit, the current is constant throughout the circuit, so the battery voltage is equal to the sum of the voltage drop in each part of the series circuit.

        V = i (R₁ + R₂ + R₃)

       

in the exercise indicate that all resistance has the same value

         R₀ = R₁ = R₂ = R₃

        V = i 3 R₀

        V = 3 V₀

         V₀ = i R₀

          V₀= V / 3

the voltage across each resistor is one third of the battery voltage

6 0
3 years ago
A can of tuna, starting from rest, is dropped off a building. If it is only being pulled down by gravity (-9.8 m/s2) and it hits
tia_tia [17]

Answer:

<h3>50.23m</h3>

Explanation:

The distance talks about how far an object has travelled.

Given

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to get the distance Δx, we will use the formula;

S = ut+1/2gt²

S = 0(3.2)+1/2(-9.8)(3.2)²

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S = -50.23m

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3 years ago
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