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exis [7]
1 year ago
14

Assume that the ammeter in the figure below is removed and the current that flows through the 4.0Ω path, I3, is unknown. Determi

ne all the currents in the circuit.

Physics
1 answer:
qaws [65]1 year ago
8 0

The circuit is in parallel connection

Equivalent resistance = 1/Req = 1/R1 + 1/R2 + 1/R3

From the information given,

R1 = 5

R2 = 2

R3 = 4

1/Req = 1/5 + 1/2 + 1/4 = (4 + 10 + 5)/20 = 19/20

Req = 20/19 = 1.053 ohms

I = V/R

Given that V = 12,

Current flow through circuit = 12/1.053 = 11.4 A

I1 + I2 + I3 = 11.4

I1 = 12/5 = 2.4 A

I2 = 12/2 = 6 A

I3 = 12/4 = 3A

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From the question we are told that

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    The current on the rod is  I  = 4.1 \ A

    The distance of separation(equivalent to length of the rod ) is L   = 6.3 \ m

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