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2 years ago

PLEASE HELP ME STATTTTTTTTT

Mathematics

2 answers:

Simora [160]2 years ago

5 0

Answer:

8.714285 repeated

Step-by-step explanation:

Aneli [31]2 years ago

3 0

Answer:

Step-by-step explanation:

The real estate agent can buy 8 ads for a total of $56. Next you do $61 minus $56 which equals $5. If this answer helped you please consider giving it brainliest.

- •Trix•

( Yes I know my -•Trix• is not my user but its what I would change it to if I could but I can't, please address me as Trix while commenting or talking to me here.)

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State the name of the property illustrated below.

ivanzaharov [21]

Answer:

Step-by-step explanation:

This is the associative property for addition. In informal language, it says under addition, the order of the addition is not critical.

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3 years ago

Suppose a subset of eight different days of the year is selected at random. What is the probability that each day is from a diff

goldfiish [28.3K]

Answer:

P = 0.05

Step-by-step explanation:

12 months * 30 days each = 360 days

From 306 days, we have to select 8 days = 360C8 ways(Total ways)

We want each days from different month. First, we have to select 8 month from 12 month = 12C8 ways

---By selecting 8 month, we will select a days from each month. That can be done in = 30C1 * 30C1 * .................30C1 (8 ways) [From a month with 30 days, we can select a day in 30C1 ways = 30 ways]

Therefore P = Number of ways of selecting each days from different month / Total number of ways

P = 12C8 * 30^8 / 360C8

P = 495 * 656100000000 / 6469697679132645

P = 0.0501985588982791

P = 0.05

Hence the probability that each day is from a different month is 0.05

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3 years ago

The nine-digit number that identifies the bank that a check came from is called

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Step-by-step explanation:

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3 years ago

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3 years ago

fatima claims that the distribution of u is uniform with a median of 0.4 field goal percentage. is fatima’s claim supported by t

Amanda [17]

Fatima's claim is not supported by the table because, the distribution is skewed right, with a median of 0.4 field goal advantage.

From the table, the median position is calculated as:

$\mathbf{Median = \frac{1}{5} th}$

$\mathbf{Median = 0.2\ nd }$

The 0.2nd data falls in the 0.4 field goal category.

So, the median element is:

$\mathbf{Median = 0.4}$

However, the distribution of the table are concentrated on the left.

This means that, the distribution is not uniform, instead it is skewed right.

A uniform distribution has a skewness of 0.

Hence, Fatima's claim is not supported by the table