A foul ball is hit straight up into the air with a speed of about 25 m/s. ? how high does it go? (b) how long is it in the air?
1 answer:
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We are given a series circuit with two light bulbs. In this case, the light bulbs act as resistors in series and the total resistance is:
That is the sum of all the resistances in series in the circuit. To determine the voltage we can use Ohm's law:
Where "R" is the total resistance and "I" is the current in the circuit. Replacing we get:
Answer:
The maximum height attained by the object and the number of seconds are 128 ft and 4 sec.
Explanation:
Given that,
Initial velocity u= 128 ft/sec
Equation of height
....(I)
(a). We need to calculate the maximum height
Firstly we need to calculate the time
From equation (I)
Now, for maximum height
Put the value of t in equation (I)
(b). The number of seconds it takes the object to hit the ground.
We know that, when the object reaches ground the height becomes zero
Hence, The maximum height attained by the object and the number of seconds are 128 ft and 4 sec.
Answer:
1)chest
2)deltoid
3)bicep
4)abs
5)quadriceps
6)lats
7)triceps
8)glutes
9)calves
10)hamstring
11)trapezuis
Explanation:
the explanation is the picture
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