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BartSMP [9]
3 years ago
6

What is the pH of a 4.7 x 10-9 M HCl solution? *

Chemistry
1 answer:
ValentinkaMS [17]3 years ago
4 0
11.21 or 2.93 I think
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A plastic 2L soda bottle is flexible enough that the volume of the bottle can change even without opening it. If you have an emp
Aneli [31]

Answer:  The new volume be if you put it in your freezer is 1.8 L

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=2L\\T_1=25^oC=(25+273)K=298K\\V_2=?\\T_2=-4.0^oC=((-4)+273)K=269K

Putting values in above equation, we get:

\frac{2}{298}=\frac{V_2}{269}\\\\V_2=1.8L

The new volume be if you put it in your freezer is 1.8 L

8 0
3 years ago
¿Cuántos electrones conforman un enlace doble?
Aleks04 [339]

Answer:

Cada átomo aporta dos electrones al enlace, es decir, se comparten dos pares de electrones entre dos átomos. Un ejemplo es la molécula de Oxígeno (O2).

Explanation:

6 0
3 years ago
Improvements in which area would help reduce the possibility of damage to the environment when using uranium as a fuel?
kogti [31]

Answer:

A is the answer; 'more-efficient extraction techniques

Explanation:

I just took the test and got it right :D

5 0
3 years ago
How do we know that K2CrO4 and Ba(NO3)2 are not solids?​
navik [9.2K]
I would say is because of the Boron from O?
7 0
3 years ago
A buret is filled with 0.1517 M naoh A 25.0 mL portion of an unknown acid and two drops of indicator are added to an Erlenmeyer
antiseptic1488 [7]

Answer:

molarity of acid =0.0132 M

Explanation:

We are considering that the unknown acid is monoprotic. Let the acid is HA.

The reaction between NaOH and acid will be:

NaOH+HA--->NaA+H_{2}O

Thus one mole of acid will react with one mole of base.

The moles of base reacted = molarity of NaOH X volume of NaOH

The volume of NaOH used = Final burette reading - Initial reading

Volume of NaOH used = 22.50-0.55= 21.95 mL

Moles of NaOH = 0.1517X21.95=3.33 mmole

The moles of acid reacted = 3.33 mmole

The molarity of acid will be = \frac{mmole}{volumne(mL)}=\frac{0.33}{25}=0.0132M

4 0
3 years ago
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