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arlik [135]
3 years ago
8

What are the chemical properties of noble gases?

Chemistry
2 answers:
saw5 [17]3 years ago
8 0
Some chemical gases found in the periodic table are helium/2He and nitrogen/N,oxygen/O2,Hydrogen/H2 some gases like helium and oxygen are fresh air because their not polluted air like Nitrogen.
Arturiano [62]3 years ago
6 0
These gases all have similar properties under standard conditions: they are all odorless, colorless, monatomic gases with very low chemical reactivity. The six noble gases that occur naturally are helium (He), Neon (Ne), Argon (Ar), Krypton (Kr), Xenon (Xe), and Radon (Rn).
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anzhelika [568]
The final temperature of the water will be 31.2 °C... i don’t know the second one sorry :(
3 0
3 years ago
If 56 grams of notrogen are used up by the reaction, how many grams of amonia will be produced? 1N2+3H2--> 2NH3
djverab [1.8K]
1 mole of N2 produces 2 moles of NH3
OR...
14 x 2 grams of N2 produces 2(14 +3) grams of NH3
1 gram of N2 produces 34/28 grams of NH3
therefore, 56 grams produce (34/28 )x 56 =68 grams of NH3 

the answer thus would be 68 grams of NH3
5 0
3 years ago
Which metal will displace nickel in a compound? A. Tin B. Arsenic C. Zinc D. Platinum
Sophie [7]
Which metal will displace nickel in a compound? it zink is the  metal
8 0
4 years ago
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Precipitation reactions: Hg(NO3)2(aq) +Na2CrO4(aq) = _________ (aq) + NaNO3 (s)
valina [46]
The completed and balanced equation is:
<span>Hg(N<span>O3</span><span>)2</span>+N<span>a2</span>Cr<span>O4</span>=HgCr<span>O4</span>+2Na(N<span>O3</span>)
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5 0
3 years ago
After decaying for 48 hours, one-sixteenth (1/16) of the original mass of a radioisotope sample remains unchanged. What is the h
Hunter-Best [27]

The half-life of this radioisotope : 12 hr

<h3>Further explanation </h3>

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.  

Usually radioactive elements have an unstable atomic nucleus.  

General formulas used in decay:  

\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}

t = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

t=48 hr

\tt \dfrac{Nt}{No}=\dfrac{1}{16}

The half-life :

\tt \dfrac{1}{16}=\dfrac{1}{2}^{(48/t\frac{1}{2} )}\\\\(\dfrac{1}{2})^4=(\dfrac{1}{2})^{48/t\frac{1}{2}}\\\\4=48/t\frac{1}{2}\\\\t\frac{1}{2}=12~hr

7 0
3 years ago
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