Answer:
9
Explanation:
n-factor of NaOH = 1
OH⁻ concentration = Normality of NaOH
= Molarity x n-factor
= 10⁻⁵ x 1
= 10⁻⁵
Now, pOH = -㏒(OH⁻)
pOH = -㏒(10⁻⁵)
pOH = 5
We know pH + pOH = 14
pH = 14 - 5 = 9
∴pH of 10⁻⁵M NaOH is 9
HALOGENS have 7 electrons in their final shell regardless if the total number of atoms. These 7 electrons would be shared between the 's' and 'p' orbital in the form
ns² np⁵ (the same as the question). Attached is a table that highlights the fact that halogens have the same form in terms of the valence electrons.
Answer: The work done for the given process is -2188.7 J
Explanation:
To calculate the amount of work done for an isothermal process is given by the equation:

W = amount of work done = ?
P = pressure = 50.0 atm
= initial volume = 542 L
= final volume = 974 L
Putting values in above equation, we get:

To convert this into joules, we use the conversion factor:

So, 
The negative sign indicates the system is doing work.
Hence, the work done for the given process is -2188.7 J