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tatiyna
4 years ago
10

A house is maintained at 1 atm and 24°C, and warm air inside a house is forced to leave the house at a rate of 90 m3/h as a resu

lt of outdoor air at 5.5°C infiltrating into the house through the cracks. Determine the rate of net energy loss of the house due to mass transfer. The gas constant of air is R
Physics
1 answer:
lisov135 [29]4 years ago
3 0

Hope it helps : )

Specific heat of air at constant pressure = 1.005KJ/kg-K Apparently the hot air leaves the house while equal quantity of the cool air passes inside (Neglecting the small specific volume changes between the hot and the cold air) So the situation can be sampled as a scenario where there is continuous draw down of the thermal energy from the air.

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The acceleration of a bus is given by ax (t) = at, where a = 1.2 m/s3.If the bus's velocity at time t = 1.0s is 5.0 m/s, what is
goldenfox [79]

We are given the acceleration of the bus as a function of time:

a(t) = 1.2t

Let the velocity also be a function of time v(t).

Since a(t) is the change of v(t) over time, we can use the fundamental theorem of calculus to determine the velocity at t = 2s, or v(2), given that:

a(t) = 1.2t

v(1) = 5

v(2) - v(1) = \int\limits^2_1{a(t)}\,dt

v(2) - 5 = \int\limits^2_1{1.2t}\,dt

v(2) - 5 = 0.6t² evaluated between t = 1 and t = 2

v(2) - 5 = 0.6(4) - 0.6(1)

v(2) = 1.8 + 5

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3 years ago
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tensa zangetsu [6.8K]

Answer:

A

Explanation:

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6 0
3 years ago
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Greg bought 12 bags of dog treats that were each 50 grams. How many kilograms is this?​
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A seesaw made of a plank of mass 10.0 kg and length 3.00 m is balanced on a fulcrum 1.00 m from one end of the plank. A 20.0-kg
lidiya [134]

Answer:

7.5 kg

Explanation:

We are given that

m_1=10 kg

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Distance of fulcrum from one end of the plank=1 m

m_2=20 kg

We have to find the mass must be on the other end if the plank remains balanced.

Let m be the mass must be on the other end if the plank remains balanced.

In balance condition

20\times 1=10\times (1.5-1)+m\times (1.5+0.5)

20=10(0.5)+2m

20=5+2m

2m=20-5=15

\implies m=\frac{15}{2}

m=7.5 kg

Hence, mass 7.5 kg   must be on the other end if the plank remains balanced.

3 0
3 years ago
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VikaD [51]

Answer:

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