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iren2701 [21]
2 years ago
13

What does 10% humidity in a weather report indicate?

Chemistry
2 answers:
eduard2 years ago
8 0

Answer:

B

Explanation:

30%-50% is considered moderate. Anything below 30% is considered dry, anything above 50% is considered high. I hope this helps!

GalinKa [24]2 years ago
3 0

Answer:

B

the humidity is the % of water in the air and it is out of 100% of the air. so 10/100 is low

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What is the concentration of a solution containing 0.32 moles of NaCl in 3.4 liters?
dsp73
Get the molarity we need to divide the number of moles of NaCl by the volume of the solution. So, 0.32 moles NaCl divided by 3.4 L, and that gives 0.094 M NaCl.
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Order the terms according to the path followed by oxygen during cellular respiration.​
MArishka [77]

Answer:

Outside air

Nose

Lungs

Bloodstream

Cell

Explanation:

We breathe in oxygen from the outside air in through our nose and it travels to our lungs. Inside our lungs, we have Avioli's that diffuse oxygen into our bloodstream and the bloodstream helps the oxygen travel into our cells.

Hope this helps :)

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In the game of economics, goods are objects that fulfill peoples needs and ____.
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Goods are objects that fulfill peoples needs and wants.


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2 years ago
A compound is 40% carbon, 6.7% hydrogen, and 53.3% oxygen. What is the empirical formula?
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                           O        H        C

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Ratio                  1.00   2.00    1.00

Possible empirical formula = OH_{2}C

6 0
3 years ago
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A metal X from two oxide A and B .3.oogm of A and B contain 0.72 and 1.16g of oxygen respectively.calculate the maases of metal
devlian [24]

Answer:

Explanation:

Firstly, we have to determine the mass of metal X. We can do that by interpreting the first and second statement mathematically.

Metal X can form 2 oxides (A and B).

A + B = 3g

The mass of oxygen in A is 0.72g and the mass of oxygen in B is 1.16g.

The mass of metal X in the two oxides will be the same because it's the same metal.

Thus, we represent the mass of the metal in the two oxides as 2X.

2X + 0.72 + 1.16 = 3

2X + 1.88 = 3

2X = 3 - 1.88

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X = 0.56

<u>Thus, 0.56 g of the metal combines with 0.72g of oxygen in A and 1.16 g of oxygen in B.</u>

Thus, mass of metal (X) in 1g of oxygen in A is

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X ⇒ 1

X = 1 × 0.56/0.72

X = 0.78 g

Hence, 0.78g of the metal will combine with 1g of oxygen for A

Also, mass of metal (X) in 1g of oxygen in B is

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X = 1×0.56/1.16

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Thus, 0.48g of the metal will combine with 1g of oxygen for B

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