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mrs_skeptik [129]
3 years ago
8

Which series of labels correctly identifies the indicated structures in this sketch of a cell viewed under a microscope? A.mitoc

hondrion B.nucleolus C.Golgi apparatus D.chromatin E.ribosome F.lysosome A.Golgi apparatus B.nucleolus C.endoplasmic reticulum D.mitochondrion E.ribosome F.lysosome A.endoplasmic reticulum B.nucleus C.Golgi apparatus D.mitochondrion E.vesicle F.ribosome A.mitochondrion B.nucleus C.Golgi D.endoplasmic reticulum E.lysosome F.vesicle A series of four elongated structures is labeled A. The center most portion of the central circular structure is labeled B, a curved structure with several extensions to the right of the central circular structure is labeled C, the oval structure with a series of ovals running across the inside is labeled D, the smallest of the three sized circles is labeled E and the largest of these is labeled F.

Chemistry
2 answers:
kifflom [539]3 years ago
4 0

Answer:

for the first it is B i do not know for the second

Explanation:

i took the quiz hope this helped

KATRIN_1 [288]3 years ago
4 0

Answer:

A Golgi apparatus

B Nucleolous

C endoplasmic reticulum

D Mitochondrion

E Ribosome

F Lysosome

Explanation:

  • The center protion of the cell is called the nucleolous, so B is nucleolous
  • Those elongated structures are the Golgi apparatus (A)
  • The endoplasmic reticulum is a curved  structure near the nucleolous, so C is endoplasmic reticulum
  • The small circles are the ribosomes, E is ribosome
  • The largest circles are the lysosomes, F is lysosome
  • And the oval structure is the mitochondrion, D is mitochondrion

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In terms of the atmosphere, which of the following best describes the oxygen that is present?
Viktor [21]
The atmosphere is considered homogeneous. It isn’t exactly on the smallest scales but that doesn’t matter. Homogenous means the composition will be the same in any sample taken from the substance. And clearly, the atmosphere is mostly gas. So the last answer is right
6 0
2 years ago
What is the best description for a solution with a hydroxide-ion concentration equal to 1 x 10-4 m?
djverab [1.8K]

Answer:

This is a basic solution

Explanation:

To be able to provide a succint description of this solution, from the given parameters we can deduce the pH of the solution.

Given parameters:

Concentration of OH⁻ = 1 x 10⁻⁴M

Solution

          We knonw that pOH = -log₁₀[OH⁻]

                   pOH = -log₁₀ 0.0001 = - (-4) = 4

For an aqeous solution:

                  pH + pOH = 14

                  pH = 14 - 4 = 10

The pH of the solution has been derieved to be 10

This is a basic solution

7 0
3 years ago
Pls help will give brainliest
vlada-n [284]

The mass of a present which has a density of 2.15 kg/L and volume of 3650 mL is 7.74 kg.

<h3>How do we calculate mass?</h3>

Mass of any substance will be calculate by using the density and volume by using the below equation as:

Density = Mass / Volume

Given that,

Density of Christmas present = 2.15 kg/L

Volume of present = 3,650 mL = 3.6L

On putting values, we get

Mass = (2.15)(3.6) = 7.74

Hence required mass of Christmas present is 7.74 kg.

To know more about density, visit the below link:
brainly.com/question/10441359

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4 0
2 years ago
Explain the energy transformation that occurs when food is digested.
Dafna11 [192]

A, is the correct answer.  Food stores chemical energy. Our movement is mechanical energy. therefore Chemical energy transforms into mechanical energy. Happy to help :D

8 0
3 years ago
Read 2 more answers
A species has the following MO configuration: (σ1s)2(σ1s*)2(σ2s)2(σ2s*)2(σ2p)2(π2p)2. This substance is:_______.
Goshia [24]

Answer :  The correct option is, (a) paramagnetic with two unpaired electrons.

Explanation :

According to the molecular orbital theory, the general molecular orbital configuration will be,

(\sigma_{1s}),(\sigma_{1s}^*),(\sigma_{2s}),(\sigma_{2s}^*),(\sigma_{2p_z}),[(\pi_{2p_x})=(\pi_{2p_y})],[(\pi_{2p_x}^*)=(\pi_{2p_y}^*)],(\sigma_{2p_z}^*)

As there are 14 electrons present in the given configuration.

The molecular orbital configuration of molecule will be,

(\sigma_{1s})^2,(\sigma_{1s}^*)^2,(\sigma_{2s})^2,(\sigma_{2s}^*)^2,(\sigma_{2p_z})^2,[(\pi_{2p_x})^1=(\pi_{2p_y})^1],[(\pi_{2p_x}^*)^0=(\pi_{2p_y}^*)^0],(\sigma_{2p_z}^*)^0

The number of unpaired electron in the given configuration is, 2. So, this is paramagnetic. That means, more the number of unpaired electrons, more paramagnetic.

Hence, the correct option is, (a) paramagnetic with two unpaired electrons.

3 0
3 years ago
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