Answer:
F = 2.26 × 10⁻³ N
Explanation:
given,
length of rod = 11 cm
charge = 19 nC
linear charge density = 3.9 x 10⁻⁷ C/m
electric force at 2 cm away.
F = E q
integrating from 0.02 to 0.02 + L
F = 2.26 × 10⁻³ N
<u>Given data:</u>
Voltage (V) = 120 V,
Power (P) = 50.4 Watts,
current flowing (I) = ?
Power is nothing but the rate of doing work. Hence W/t represents electric Power (P).
Electric Power (P) = V.I Watts
This equation can be used to calculate the power consumption by any electrical device that is connected in a circuit.
In the given question, we need to determine the Current flowing through the circuit(bulb).
From the equation,
P = V.I Watts
50.4 = 120 × I
I = 50.4/120
I = 0.42 Amp
<em>Current flowing through the circuit is 0.42 Amperes. </em>
Our eyes detect light only within a range of frequencies called visible light.
Answer:
a) w = 31.4 rad / s, b) a = 118.4 m / s²
Explanation:
a) let's reduce to the SI system
w = 5 rev / s (2pi rad / 1 rev)
w = 31.4 rad / s
b) the expression for the centripetal acceleration is
a = v² / r
linear and angular variables are related
v = w r
we substitute
a = w² r
a = 31.4² 0.120
a = 118.4 m / s²
VO2 max is considered to be the most valid measure<span> of </span>cardio respiratory fitness<span>. It </span>measures<span> the capacity of the heart, lungs, and blood to transport oxygen to the working muscles, and </span>measures<span> the utilization of oxygen by the muscles during exercise.</span>