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Gala2k [10]
3 years ago
13

How far away from the sun would a planet mercury's size have to be before it would have an atmosphere?

Physics
1 answer:
Elza [17]3 years ago
4 0
It's 87.97 days of the orbital period going round the sun it's days of the shortest of all planets in the solar system.
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A perfectly elastic collision occurs between a 15.0-kg mass traveling at 3.50 m/s and a 9.00-kg mass traveling at 2.35 m/s. if t
BaLLatris [955]
Momentum is conserved in a collision. Momentum is mass*velocity, so you can find your answer by calculating initial and final momentums and setting them equal to each other.

15kg * 3.50 m/s + 9kg * 2.35 m/s = 73.65 kg m/s

73.65 = 9 * 2.8 + 15x

solve for x
x= 3.23

The final velocity is 3.23 m/s
5 0
3 years ago
8. Il An 8.00 kg package in a mail-sorting room slides 2.00 m down a
Vitek1552 [10]

Answer:

See below

Explanation:

Normal force = m g cos 53 = 8 kg * 9.8 m/s^2 * cos 53 = 47.1823 N

  no work is done by this force

Force friction = coeff friction * force normal = .4 * 47.1823 = 7.55 N

   work of friction = 7.55 * 2 m = 15.1 j

Force Downplane = mg sin 53 = 62.61  N

    work = 62.61 * 2 = 125.22 j

Net Force downplane =   force downplane - force friction = 55.06 N

net Work = force * distance = 55.06 N * 2 M = 110.12 j

3 0
2 years ago
What is a literature review?<br>​
almond37 [142]

Answer: A literature review consists of an overview, a summary, and an evaluation (“critique”) of the current state of knowledge about a specific area of research.

Explanation:

7 0
2 years ago
How would the gravitational force between the earth and the moon change if the moon had half the mass?
Vikki [24]

The moon's gravity, combined with the waltz of Earth and the moon around their center of mass, forces the oceans into an oval shape, with two simultaneous high tides. ... If the moon were half its mass, then the ocean tides would have been correspondingly smaller and imparted less energy to it.

5 0
3 years ago
A pair of in-phase stereo speakers is placed side by side, 0.764 m apart. You stand directly in front of one of the speakers, 2.
Goryan [66]

Answer:

f = 2858.33 Hz

Explanation:

given,

distance between speaker (A) and the person = 2.34 m

Distance between speaker (B) and the person is AB =

            =\sqrt{(0.764)^2 + (2.34)^2}

            = 2.46 m

path difference d = BP - AP

                             = 2.46  - 2.34 m

                             = 0.12 m

now,    λ = 0.12

speed of sound =  343 m/s

    f= \dfrac{c}{\lambda}

    f= \dfrac{343}{0.12}

              f = 2858.33 Hz

the lowest frequency that will produce constructive interference is equal to

f = 2858.33 Hz

7 0
2 years ago
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