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3 years ago

How far away from the sun would a planet mercury's size have to be before it would have an atmosphere?

Physics

1 answer:

Elza [17]3 years ago

4 0

It's 87.97 days of the orbital period going round the sun it's days of the shortest of all planets in the solar system.

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How much heat is needed to raise the temperature of 2 kg of copper from 20º to 30ºC. The specific heat of copper is 390 J/kgºC.

ryzh [129]

Answer:

7800 J

Explanation:

Heat needed = mass of copper x specific heat of copper x change in temperature

Change in temperature = 30ºC - 20ºC = 10ºC

Specific heat of copper = 390 J/kgºC

Mass of copper = 2 Kg

Substituting the given values in above equation, we get –

Heat needed = 2 Kg x 390 J/kgºC x 10ºC

= 7800 J

3 0

3 years ago

HURRY PLZ

Natali [406]

The answer correct is C:The cell is most likely prokaryotic ,but it could be eukaryotic since some unicellular are eukaryotic.

5 0

3 years ago

What is the difference between longitudinal and transverse waves?

Greeley [361]

Transverse Waves: Displacement of the medium is perpendicular to the direction of propagation of the wave. ... Longitudinal Waves: Displacement of the medium is parallel to the direction of propagation of the wave.

3 0

3 years ago

Two small objects each with a net charge of +Q exert a force of magnitude F on each other. We replace one of the objects with an

Alona [7]

Answer:

F'= 4F/9

Explanation:

Two small objects each with a net charge of +Q exert a force of magnitude F on each other. If r is the distance between them, then the force is given by :

$F=\dfrac{kQ^2}{r^2}$ ...(1)

Now, if one of the objects with another whose net charge is + 4Q is replaced and also the distance between +Q and +4Q charges is increased 3 times as far apart as they were. New force is given by :

$F'=\dfrac{kQ\times 4Q}{(3r)^2}\\\\F'=\dfrac{4kQ^2}{9r^2}$ .....(2)

Dividing equation (1) and (2), we get :

$\dfrac{F}{F'}=\dfrac{\dfrac{kQ^2}{r^2}}{\dfrac{4kQ^2}{9r^2}}\\\\\dfrac{F}{F'}=\dfrac{kQ^2}{r^2}\times \dfrac{9r^2}{4kQ^2}\\\\\dfrac{F}{F'}=\dfrac{9}{4}\\\\F'=\dfrac{4F}{9}$

Hence, the correct option is (d) i.e. " 4F/9"

7 0

3 years ago

The image shows a roller coaster.

mariarad [96]

I believe the answer is c but I’m not 100% sure

8 0

3 years ago