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Gala2k [10]
3 years ago
13

How far away from the sun would a planet mercury's size have to be before it would have an atmosphere?

Physics
1 answer:
Elza [17]3 years ago
4 0
It's 87.97 days of the orbital period going round the sun it's days of the shortest of all planets in the solar system.
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What's is the origin of Neptune's moon Triton?​
Elden [556K]
Triton was discovered by British astronomer William Lassell on October 10, 1846, just 17 days after the discovery of Neptune.

Triton is named after the Greek sea god Triton (Τρίτων), the son of Poseidon (the Greek god corresponding to the Roman Neptune).
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3 years ago
What happens to the density of gas when it compressed
Stella [2.4K]
When a gas is compressed, its particles are pushed closer together so it is more dense.
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3 years ago
Two balls are kicked with the same initial speeds. Ball A was kicked at the angle 20° above horizontal and ball B was kicked at
GREYUIT [131]

Answer:

Ball A

Explanation:

Let the initial speed of the balls be u .

Angle of projection for ball A = 20°

Angle of projection for ball B = 75°

As we know that at highest point, the ball has only horizontal speed which always remains constant throughout the motion because the acceleration in horizontal direction is zero.

Speed of ball A at highest point = u Cos 20° = 0.94 u

Speed of ball B at highest point = u Cos 75° = 0.26 u

So, the ball A has bigger speed than B.

5 0
3 years ago
Select the correct answer.
wolverine [178]
The answer is C in this question.
5 0
3 years ago
Read 2 more answers
Consider massive gliders that slide friction-free along a horizontal air track. Glider A has a mass of 1 kg, a speed of 1 m/s, a
mamaluj [8]

Answer:

0.167m/s

Explanation:

According to law of conservation of momentum which States that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision. The bodies move with a common velocity after collision.

Given momentum = Maas × velocity.

Momentum of glider A = 1kg×1m/s

Momentum of glider = 1kgm/s

Momentum of glider B = 5kg × 0m/s

The initial velocity of glider B is zero since it is at rest.

Momentum of glider B = 0kgm/s

Momentum of the bodies after collision = (mA+mB)v where;

mA and mB are the masses of the gliders

v is their common velocity after collision.

Momentum = (1+5)v

Momentum after collision = 6v

According to the law of conservation of momentum;

1kgm/s + 0kgm/s = 6v

1 =6v

V =1/6m/s

Their speed after collision will be 0.167m/s

6 0
3 years ago
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