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3 years ago

A. An open parallel circuit

Physics

1 answer:

uysha [10]3 years ago

3 0

Answer: Open Series Circuit

Explanation: In a Series Circuit everything is connected together, but in Parallel Circuit it is not, it's Parallel R1, R2, etc.

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A 1.0 kg football is given an initial velocity at ground level of 20.0 m/s [37 above horizontal]. It gets blocked just after re

stepan [7]

Refer to the diagram shown below.

Neglect air resistance.
The horizontal component of the launch velocity is
(20 m/s)*cos(37°) = 15.973 m/s
The vertical component of the launch velocity is
(20 m/s)*sin(37°) = 12.036 m/s

The acceleration due to gravity is g =9.8 m/s².
The time, t s, for the ball to reach a height of 3 m is given by
(12.036 m/s)*(t s) - (1/2)*(9.8 m/s²)*(t s)² = (3 m)
12.036t - 4.9t² - 3 = 0
2.4543t - t² - 0.6122 = 0
t² - 2.4563t + 0.6122 = 0
Solve with the quadratic formula.
t = (1/2)[2.4563 +/- √(6.0334 - 2.4488)]
t = 2.1748 or 0.2815 s
The ball reaches a height of 3 m twice.
The first time it reaches 3 m height is 0.2815 s.

Part a.
The vertical velocity when t = 0.2815 s is
Vy = 12.036 - 9.8*0.2815
= 9.2773 m/s
The horizontal component of velocity is Vx = 15.973 m/s
The resultant velocity is
√(9.2773² + 15.973² ) = 18.47 m/s
Answer:
The velocity at a height of 3.0 m is 18.5 m/s (nearest tenth)

Part b.
The horizontal distance traveled is
d = (15.973 m/s)*(0.2815 s) = 4.4964 m
Answer:
The horizontal distance traveled is 4.5 m (nearest tenth)

6 0

3 years ago

A 45.0 kg skier testing a new competitive ski wax drops off a ledge, goes into a crouch and goes straight down a slope of 10.0◦

Neko [114]

Answer:

v = 21.03 m/s

Explanation:

given,

mass of skier = 45 kg

the slope of the snow = 10.0◦

coefficient of friction = 0.114

distance traveled = 300 m

speed = ?

Acceleration = g sin θ - µ g Cos θ

= 9.8 × Sin (10°) - 0.10 × 9.8 × Cos(10°)

= 0.737 m/s²

using equation of motion

v² = u² + 2 a s

v² = 0 + 2 × 0.737 × 300

v = 21.03 m/s

Speed of skier's after travelling 300 m speed is equal to 21.03 m/s

6 0

3 years ago

Dr. Clairmont will have his psychology students training dogs from the local animal shelter to sit using various types of reinfo

olga2289 [7]

Answer:Habituation is a simple learned behavior in which an animal gradually stops responding to a repeated stimulus.

Imprinting is a specialized form of learning that occurs during a brief period in young animals—e.g., ducks imprinting on their mother.

In classical conditioning, a new stimulus is associated with a pre-existing response through repeated pairing of new and previously known stimuli.

In operant conditioning, an animal learns to perform a behavior more or less frequently through a reward or punishment that follows the behavior.

Some animals, especially primates, are capable of more complex forms of learning, such as problem-solving and the construction of mental maps.

Introduction

If you own a dog—or have a friend who owns a dog—you probably know that dogs can be trained to do things like sit, beg, roll over, and play dead. These are examples of learned behaviors, and dogs can be capable of significant learning. By some estimates, a very clever dog has cognitive abilities on par with a two-and-a-half-year-old human!

Explanation:

6 0

3 years ago

A small plane starts from rest and accelerates uniformly to the east to a takeoff velocity of 70 m/s in 5 seconds. What is the p

Rainbow [258]

Hope this helps, if you need clarification i got you

3 0

3 years ago

An ac generator has a maximum emf output of 150 V. What is the rms current in the circuit when the generator is connected to a 3

natima [27]

This is an insidious question. Quite frankly, I would not have
expected to see it here on Brainly. But I'm ready to play the
cards that you have dealt me.

None of the choices offered is a correct solution.

If the output of the AC generator is nice and sinusoidal, and
its maximum (peak) emf is 150 volts, then its RMS emf is

   (1/2) (150) (√2) = 106.07 volts.

The resistor's dissipation is

   Power = (current) x (voltage) .

If the resistor is dissipating its full rated 35W, then

   35W = (current) x (106.07 V)

Divide each side by 106.07 V:

   RMS Current = (35W) / (106.07 V) = 0.33 Ampere .
_________________________________________

Looking over the choices offered . . .

The largest choice ... 3.1 A ... is the current in a resistor
that is dissipating 35W if the voltage is

   (35W / 3.1A) = 11.29 volts .

The smallest choice ... 1.2 A ... is the current in a resistor
that is dissipating 35W if the voltage is

   (35W / 1.2A) = 29.17 volts .

Whatever you meant the so-called "150 V" of the generator
to represent ... whether the RMS sinusoidal, peak sinusoidal,
peak square-wave, RMS square-wave, DC, average, etc. ...
none of the choices for current, in combination with any of these
generators, would dissipate 35W.

3 0

4 years ago