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stira [4]
3 years ago
12

For two years, two samples of fish were taken from a pond. Each year, the second sample was taken six months after the first sam

ple.
2 tables. A 3-column table with 4 rows. Column 1 is labeled Year 1 with entries trout, catfish, bass, all fish. Column 2 is labeled Sample 1 with entries 3, 9, 8, 20. Column 3 is labeled Sample 2 with entries 5, 9, 6, 20. The second table is a 3-column table with 4 rows. Column 1 is labeled Year 1 with entries trout, catfish, bass, all fish. Column 2 is labeled Sample 1 with entries 8, 10, 2, 20. Column 3 is labeled Sample 2 with entries 10, 9, 1, 20.

Make an inference about which fish increased its predicted average population from Year 1 to Year 2.
All three types of fish increased their predicted average population.
Trout increased its predicted average population.
Bass increased its predicted average population.
None of the fish increased their predicted average population.
Mathematics
2 answers:
Pie3 years ago
8 0

Answer:

the answer is D E

Step-by-step explanation:

i just took it trust me

boyakko [2]3 years ago
4 0

Answer:

d and e

Step-by-step explanation:

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Someone help with this, please. It's for my test ;(
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Answer:

y=4

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Lets say test tubes = t, and beakers = b

1 pack of (t) is $4 less than 1 pack of (b)

Since i have no prior information we are going to use variables for this equation:

1t (1 pack of test tubes) is $4 less than 1b (1 set of beakers)

so to quantify the equation, we have 8t and 12b.

if b is a number that IS quantifiable such as $5 we can easily figure out this answer.

Lets use and example that 1 set of beakers is $8, if we multiply $8 by 12 (the number of sets of beakers), we get: 96

Using the same example, if 1t is $4 less than 1b than 1t = $4. So, if we multiply $4 by 8 (the amount of packs of test tubes), we get: 32

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