PLEASE HELP ASAP!! will mark!find the zeros of the function. no links
2 answers:
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Answer:
C
Step-by-step explanation:
To find the appropriate equation, notice the red graph has shifted up about 6 units. This means that which is shifted by -3 will move 6 up. -3+6= 3. This means the function will have +3. Only B and C are options. Now test a point. Notice the red function crosses the y-axis at about 5 or 6 when x=0.
This function doesn't match.
This function matches. Option C is correct.
Answer:
117
Step-by-step explanation:
First think of the square that was removed. All 4 sides are equal but you don't know the length so lets gives them the variable X.
So to find the area of the rectangle, insert those variables into the area equation for a rectangle.
(RV + (X) ) (PT +(X)) = rectangle area
Now you are given what the area is if you remove the square. So subtract the the square's area from the equation above and set it equal to the size they told you.
(RV + (X)) (PT + (X)) - [(X)(X)] = 92
rectangle - square = remaining area
Now plug in the numbers you know and solve for X.
(8 + X) (4 + X) - ((X)(X)) = 92
Use FOIL to multiply the first part of the equation (first, outer, inner, last)
32 + 8x + 4x + -
= 92
32 + 12x = 92
12x = 60
x = 5
So now you know the size of the square. Each side is 5m. So add 5m onto the top of the rectangle and onto the side. The top is 13m and the side is 9m. The area of the rectangle is the length times the height to 13 x 9 which is 117