because lighting heats up the surrounding air slowly, it realationship to thunder is currently unknown true or false

Force (f) = ?<br> mass (m) = 75kg<br> gravity (g) = 9.8m/s^2

Sloan [31]

Answer:

735 N

Explanation:

5 0

3 years ago

Calculate Neptune's mass given the acceleration due to gravity at the north pole is 11.529 m/s2 and the radius of Neptune at the

dolphi86 [110]

Answer:

The mass of Neptune is $1.023\times 10^{26}$ kilograms.

Explanation:

From Newton's Law of Gravitation, the gravitational acceleration of Neptune is determined by the following formula:

$g = \frac{G\cdot M}{R^{2}}$ (1)

Where:

$G$ - Gravitational constant, measured in cubic meters per kilogram-square second.

$M$ - Mass of the planet, measured in kilograms.

$R$ - Radius of the planet, measured in meters.

$g$ - Gravitational acceleration, measured in meters per square second.

If we know that $G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}$ , $g = 11.529\,\frac{m}{s^{2}}$ and $R = 24.340\times 10^{6}\,m$ , then the mass of Neptune is:

$M = \frac{g\cdot R^{2}}{G}$

$M = \frac{\left(11.529\,\frac{m}{s^{2}}\right)\cdot (24.340\times 10^{6}\,m)^{2} }{6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}} }$

$M = 1.023\times 10^{26}\,kg$

The mass of Neptune is $1.023\times 10^{26}$ kilograms.

5 0

3 years ago

An object moving with initial velocity 10 m/s is subjected to a uniform acceleration of 8 m/s ^² . The displacement in the next

Greeley [361]

365 Everyday Value, Organic Creamy Peanut Butter. Net Carbs: 4 grams per serving. ...
Classic Peanut Butter by Justin's. Net Carbs: 5 grams. ...

8 0

3 years ago

At what speed must a 0.6 kg stone be thrown in order that it has a relativistic mass of 0.76 kg? (c = 3.00 x 10^8 m/s) A) 0.6976

soldier1979 [14.2K]

Answer:

The speed of the stone is 0.6138 c.

(B) is correct option.

Explanation:

Given that,

Mass of stone m= 0.6

Relativistic mass = 0.76

We need to calculate the speed

Using formula of rest mass

$m_{r}=\dfrac{m_{0}}{\sqrt{1-\dfrac{v^2}{c^2}}}$

$v^2=(\dfrac{m_{0}^2}{m_{r}^2}-1)c^2$

Put the value into the formula

$v^2=(\dfrac{0.6^2}{0.76^2}-1)\times c^2$

$v=\sqrt{0.37673c^2}$

$v=0.6138c$

Hence, The speed of the stone is 0.6138 c.

3 0

3 years ago

A meteorite has a speed of 90.0 m/s when 850 km above the Earth. It is falling vertically (ignore air resistance) and strikes a

Schach [20]

Before it hits the sand bed, the meteorite is accelerating uniformly with $g=9.80\dfrac{\rm m}{\mathrm s^2}$ , so that its speed $v$ satisfies

$v^2-{v_0}^2=-2g\Delta y$

where $v_0=90.0\dfrac{\rm m}{\rm s}$ is its initial speed and $\Delta y=(0-850)\,\mathrm{km}=-850\,\mathrm{km}$ is its change in altitude. Notice that we're taking the meteorite's starting position in the atmosphere to be the origin, and the downward direction to be negative. Now,

$v^2-\left(-90.0\dfrac{\rm m}{\rm s}\right)^2=-2\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)(-850,000\,\mathrm m)\implies\boxed{v=4080\dfrac{\rm m}{\rm s}}$

3 0

3 years ago

because lighting heats up the surrounding air slowly, it realationship to thunder is currently unknown true or false​

because lighting heats up the surrounding air slowly, it realationship to thunder is currently unknown true or false