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3 years ago

13

An object moves with a constant speed of 20 m/s on a circular track of radius 100 m. What is the tangential acceleration of the

object?

1 answer:

MissTica3 years ago

4 0

Answer:4s^-1

Explanation:Tangential Acceleration=v^2/r=(20)²/100=400/100

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Answer:

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v = \sqrt{R\cdot (\frac{N}{m}+g) }

v = \sqrt{(5\,m)\cdot (\frac{6\,N}{0.8\,kg} +9.807\,\frac{kg}{m^{2}} )}

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The normal force on the car when it is at the bottom of the track is:

N=m\cdot (\frac{v^{2}}{R}+g )

N = (0.8\,kg)\cdot \left(\frac{(9.302\,\frac{m}{s} )^{2}}{5\,m}+ 9.807\,\frac{m}{s^{2}} \right)

N=21.690\,N

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