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grandymaker [24]
3 years ago
8

How many liters of a 6.0 M solution of acetic acid contain 0.0030 moles​

Chemistry
1 answer:
fenix001 [56]3 years ago
5 0

Answer: Least Common Multiplier of a6m, 0.003 moles 0.01elamos

Steps 6m, 0.003 moles

Compute an expression comprised of Factors that appear either in a6m or 0.003 moles

= 0.018elamos

Explanation:

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Consider this initial-rate data at a certain temperature for the reaction described by N2O3(
Yuliya22 [10]

<span><span>N2</span><span>O3</span><span>(g)</span>→NO<span>(g)</span>+<span>NO2</span><span>(g)</span></span>

<span><span>[<span>N2</span><span>O3</span>]</span> Initial Rate</span>
<span>0.1 M     r<span>(t)</span>=0.66</span> M/s
<span>0.2 M     r<span>(t)</span>=1.32</span> M/s
<span>0.3 M     r<span>(t)</span>=1.98</span> M/s

We can have the relationship:

<span>(<span><span>[<span>N2</span><span>O3</span>]/</span><span><span>[<span>N2</span><span>O3</span>]</span>0</span></span>)^m</span>=<span><span>r<span>(t)/</span></span><span><span>r0</span><span>(t)
However,
</span></span></span>([N2O3]/[N2O3]0) = 2

Also, we assume m=1 which is the order of the reaction.

Thus, the relationship is simplified to,

r(t)/r0(t) = 2

r<span>(t)</span>=k<span>[<span>N2</span><span>O3</span>]</span>

0.66 <span>M/s=k×0.1 M</span>

<span>k=6.6</span> <span>s<span>−<span>1</span></span></span>

6 0
3 years ago
Read 2 more answers
Mg + 2AgNO3 -&gt; 2Ag + Mg(NO3)2
9966 [12]

Answer:

Explanation:

We'll assume there is an excess of silver nitrate, so that all 12.0 moles of the magnesium (Mg) will react.

The balanced equation tells us we'll obtain 2 moles of Ag for every 1 mole of magnesium, for a molar ratio of 2/1.

Starting with 12.00 moles Mg, we would therefore hope to find twice that, or 24.00 moles of Ag.

To convert to grams, find the molar mass of Ag from the periodic table.

Ag has a molar mass of 107.9 (to 4 sig figs) grams/mole.

(24.00 moles)*(107.9 grams/mole) = 2590 grams (4 sig figs)

Hands off, it's mine.

5 0
2 years ago
What is 1 Oz equal to in grams?
lakkis [162]
1 Oz is 28.3495 grams

hope this helps!
4 0
3 years ago
Read 2 more answers
Hexane and octane are mixed to form a 45 mol% hexane solution at 25 deg C. The densities of hexane and octane are 0.655 g/cm3 an
avanturin [10]

Answer:

The required volume of hexane is 0.66245 Liters.

Explanation:

Volume of octane = v=1.0 L=1000 cm^3

Density of octane= d = 0.703 g/cm^3

Mass of octane ,m= d\times v=0.703 g/cm^3\times 1000 cm^3=703 g

Moles of octane =\frac{m}{114 g/mol}=\frac{703 g}{114 g/mol}=6.166 mol

Mole percentage of Hexane = 45%

Mole percentage of octane = 100% - 45% = 55%

55\%=\frac{6.166 mol}{\text{Total moles}}\times 100

Total moles = 11.212 mol

Moles of hexane :

45%=\frac{\text{moles of hexane }}{\text{Total moles}}\times 100

Moles of hexane = 5.0454 mol

Mass of 5.0454 moles of hexane,M = 5.0454 mol × 86 g/mol=433.9044 g

Density of the hexane,D = 0.655 g/cm^3

Volume of hexane = V

V=\frac{M}{D}=\frac{433.9044 g}{0.655 g/cm^3}=662.4494 cm^3\approx 0.66245 L

(1 cm^3= 0.001 L)

The required volume of hexane is 0.66245 Liters.

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3 years ago
What color is the start of the rainbow?
zheka24 [161]

Rainbows go in the order of ROYGBIV, which is an acronym for red, orange, yellow, green, blue, indigo, violet.

So, it would start off with red.

If you want to know why it starts off the rainbow, its because red has the longest wavelength, compared to the rest of the colors. (sorry I'm rambling, I got excited)

Hope this helps.

4 0
3 years ago
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