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2 years ago

Which compounds exhibit geometric isomerism? Draw and name the two isomers in each case:(b) 3-hexene

Chemistry

1 answer:

eimsori [14]2 years ago

8 0

3-hexene shows geometrical isomers .

The geometrical isomers of 3-hexene are cis-3-hexene and trans-3-hexene.

Trans isomer has a higher melting point than cis isomer . the cis isomer has high boiling point . dipole moment is low in case of trans and high in case of cis .

<h3>What is isomerism ?</h3>

it is a type of phenomena in which two or more compounds have same molecular or chemical formula but have different structure or spatial arrangement in 3D space .

<h3>Isomers :</h3>

same molecular formula but different physical or chemical properties .

<h3>What is geometrical isomers ?</h3>

it is a type of stereoisomers which have same molecular formula and same structure but different arrangement of atoms in space .

Learn more about geometrical isomerism here :

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2 years ago

When 21.45 g of KNO3 was dissolved in water in a calorimeter, the temperature fell from 25.00°C to 14.14 °C. If the heat capacit

pashok25 [27]

25.9 kJ/mol. (3 sig. fig. as in the heat capacity.)

<h3>Explanation</h3>

The process:

$\text{KNO}_3\;(s) \to \text{KNO}_3\;(aq)$ .

How many moles of this process?

Relative atomic mass from a modern periodic table:

K: 39.098;
N: 14.007;
O: 15.999.

Molar mass of $\text{KNO}_3$ :

$M(\text{KNO}_3) = 39.098 + 14.007 + 3\times 15.999 = 101.102\;\text{g}\cdot\text{mol}^{-1}$ .

Number of moles of the process = Number of moles of $\text{KNO}_3$ dissolved:

$\displaystyle n = \frac{m}{M} = \frac{21.45}{101.102} = 0.212162\;\text{mol}$ .

What's the enthalpy change of this process?

$Q = C\cdot \Delta T = 0.505 \times (25.00 - 14.14) = 5.4843\;\text{kJ}$ for $0.212162\;\text{mol}$ . By convention, the enthalpy change $\Delta H$ measures the energy change for each mole of a process.

$\displaystyle \Delta H = \frac{Q}{n} = \frac{5.4843\text{kJ}}{0.212162\;\text{mol}} = 25.8\;\text{kJ}\cdot\text{mol}^{-1}$ .

The heat capacity is the least accurate number in these calculation. It comes with three significant figures. As a result, round the final result to three significant figures. However, make sure you keep at least one additional figure to minimize the risk of rounding errors during the calculation.

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3 years ago

Which ligand binds tightest? ligand A, with a dissociation constant ( Kd ) of 10−9 M ligand D, with a percent occupancy of 80% a

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The answer will be Ligand A with a dissociation constant (Kd) of $10^{-9}$ M

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When the dissociation constant in the ligand is small (in order of nano) ( $10^{-9}$ ) it will be more tied. Due to a dissociation constant measures how much a ligand can be able to be separated from the protein so if the number is small it means that the ligand is highly binded to the protein.

On the other hand, the occupancy percentage of the ligand does not imply binding. Conversely, a High-affinity ligand binding with the proteins implies that a relatively low concentration of a ligand is adequate to occupy the maximum ligand-binding site.

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