Answer:
chain reaction
Explanation:
The description is termed a chain reaction.
During nuclear fission, a heavy radioactive isotope disintegrates rapidly into two lighter nuclei and several neutrons with the release of large amount of energy.
Each of the neutrons produced can now react with the new radionuclide to produce another new set of nuclide thereby releasing energy and several neutrons. This is called a chain reaction.
For the nuclide described above, we can express as:
²³⁶₉₂U → fission fragments(²³⁵₉₂U) + neutrons + energy
fission with the neutrons:
²³⁵₉₂U → ²³⁶₉₂U ..................................
Answer:
Molecules start out unevenly distributed and end up evenly distributed.
Explanation:
Diffusion is the process by which molecules of a substance move from a region of higher concentration to a region of lower concentration until equilibrium is attained.
Molecules start out unevenly distributed and end up evenly distributed in a particular medium. Diffusion occurs due to the particulate nature of matter. When the particles that make up a substance are concentrated at a point, the collide more often with one another causing each molecule to spread out in order to occupy all the available space.
Diffusion occurs in gases, liquids and solids but occurs fastest in gases. Diffusion can be observed for example, in the spread of the smell of a dead rat from one point in a room to every part of the room.
Answer:
C4H6
Explanation:
See attached table
Convert each of the masses into moles by dividing the mass by the molar mass of that element. That yields 3.83 moles of C and 6 moles of O. I rounded up the C to 4 moles to result in an empirical formula of C4H6
The question is incomplete; the complete question is;
A chemist must dilute 99.4 mL of 152 mM aqueous potassium dichromate (K_2Cr_2O_7) solution until the concentration falls to 55.0 mM He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits.
Answer:
0.275 L
Explanation:
From C1V1 = C2V2
Where;
C1= initial concentration of the solution 152 × 10^-3 M
V1= initial volume of the solution = 99.4 × 10^-3 L
C2 = concentration after dilution = 55 × 10^-3 M
V2 = volume after dilution = the unknown
V2 = C1 V1/C2
V2 = 152 × 10^-3 × 99.4 × 10^-3 / 55 × 10^-3
V2 = 0.275 L
Answer:
237.2 mL.
Explanation:
- We have the rule: at neutralization, the no. of millimoles of acid is equal to the no. of millimoles of the base.
(XMV) acid = (XMV) base.
where, X is the no. of (H) or (OH) reproducible in acid or base, respectively.
M is the molarity of the acid or base.
V is the volume of the acid or base.
<em>(XMV) HCl = (XMV) NaOH.</em>
<em></em>
For HCl; X = 1, M = 0.5 M, V = ??? mL.
For NaOH, X = 1, M = 1.54 M, V = 77.0 mL.
<em>∴ V of HCl = (XMV) NaOH / (XV) HCl = (</em>1)(1.54 M)(77.0 mL) / (1)(0.5 M) = <em>237.2 mL.</em>
