Answer:
Explanation:
x in (-oo:+oo)
2 < (1/2)*x-3 // - (1/2)*x-3
2-((1/2)*x)+3 < 0
(-1/2)*x+2+3 < 0
5-1/2*x < 0 // - 5
-1/2*x < -5 // : -1/2
x > -5/(-1/2)
x > 10
x in (10:+oo)
(10:+oo)
CO+2 H2=CH3OH
2.85 mol Co x (2mol H2/1 mol Co)=5.70 mol just concert to grams
5.70 mol H2 x (2 g H2/1 mol H2) =11.40 grams of H2
The volume of the cone can be calculated as follows:
volume of cone = (1/3) x pi x (radius)^2 x height .......> equation 1
We know that the height is twice the diameter, therefore:
h = 2d .............> equation 2
we also know know that the radius is half the diameter:
r = (1/2) d
d = 2r ...................> equation 3
Substitute with equation 3 in equation 2, we get:
h = 2d = 2 (2r)
h = 4r
r = (1/4) h................> equation 4
Substitute with equation 4 in equation 1, we get:
volume of cone = (1/3) x pi x (radius)^2 x height
= (1/3) x pi x (0.25 h)^2 x h
= (1/3) x pi x (1/16) h^2 x h
= (1/48) x pi x h^3
Answer:
P = 24.34 atm
Explanation:
V = 5.0L
P = ?
n = 4.75 moles
T = 39.3°C = (39.3 + 273.15)K = 312.45K
From ideal gas equation,
PV = nRT
P = pressure of the gas
V = volume of the gas
n = no. Of moles present
R = ideal gas constant = 0.082atm.L / mol.K
PV = nRT
P = nRT / V
P = (4.75 * 0.082 * 312.45) / 5
P = 121.699 / 5
P = 24.339 atm
P = 24.34 atm
The pressure of the gas is 24.34 atm
A clear chemical compound.