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Novosadov [1.4K]

2 years ago

14

Based on the activity series provided, which reactants will form products? F > Cl > Br > I CuI2 + Br2 Right arrow. Cl2

+ AlF3 Right arrow. Br2 + NaCl Right arrow. CuF2 + I2 Right arrow.

2 answers:

Sonja [21]2 years ago

8 0

Answer:

i believe the answer is a

Explanation:

agasfer [191]2 years ago

7 0

Answer: Cul2 + Br2 ->

Explanation:

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What does temperature indirectly measure? 1)Sound 2)Thermometers 3)Chemical Reactions 4)Heat

attashe74 [19]

Answer:

Heat

Explanation:

Temperature is the average thermal energy (or heat) in a substance. Sound isn't really related, thermometers measure temperature, and chemical reactions can produce heat, but none of those are measured by temperature.

3 0

2 years ago

An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respective

katovenus [111]

Answer:

The new partial pressures after equilibrium is reestablished:

$PCl_3,p_1'=6.798 Torr$

$Cl_2,p_2'=26.398 Torr$

$PCl_5,p_3'=223.402 Torr$

Explanation:

$PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)$

At equilibrium before adding chlorine gas:

Partial pressure of the $PCl_3=p_1=13.2 Torr$

Partial pressure of the $Cl_2=p_2=13.2 Torr$

Partial pressure of the $PCl_5=p_3=217.0 Torr$

The expression of an equilibrium constant is given by :

$K_p=\frac{p_1}{p_1\times p_2}$

$=\frac{217.0 Torr}{13.2 Torr\times 13.2 Torr}=1.245$

At equilibrium after adding chlorine gas:

Partial pressure of the $PCl_3=p_1'=13.2 Torr$

Partial pressure of the $Cl_2=p_2'=?$

Partial pressure of the $PCl_5=p_3'=217.0 Torr$

Total pressure of the system = P = 263.0 Torr

$P=p_1'+p_2'+p_3'$

$263.0Torr=13.2 Torr+p_2'+217.0 Torr$

$p_2'=32.8 Torr$

$PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)$

At initail

(13.2) Torr (32.8) Torr (13.2) Torr

At equilbriumm

(13.2-x) Torr (32.8-x) Torr (217.0+x) Torr

$K_p=\frac{p_3'}{p_1'\times p_2'}$

$1.245=\frac{(217.0+x)}{(13.2-x)(32.8-x)}$

Solving for x;

x = 6.402 Torr

The new partial pressures after equilibrium is reestablished:

$p_1'=(13.2-x) Torr=(13.2-6.402) Torr=6.798 Torr$

$p_2'=(32.8-x) Torr=(32.8-6.402) Torr=26.398 Torr$

$p_3'=(217.0+x) Torr=(217+6.402) Torr=223.402 Torr$

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2 years ago

How did Mendeleev set up his Periodic Table of Elements?

Ksju [112]

He set up his periodic table by the atomic mass

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2 years ago

Is chromium a transition metal

oksano4ka [1.4K]

No it is not

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7 0

3 years ago

Read 2 more answers

CAN SOMEONE PLEASE HELP MEEE :(

o-na [289]

Answer:

B

Explanation:

The water is the solvent and the sugar is the solute

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5 0

2 years ago