Li2O.. Because Li is +1 and O2 is -2
Forms when lava and magma cool (A)
From the mole ratio of the reaction as given in the equation of the reaction, the mass of calcium chloride that can be produced from 5.59 mol of hydrochloric acid is 310.245 g.
<h3>What mass of calcium chloride can be produced from 5.59 mol of hydrochloric acid?</h3>
The mass of calcium chloride that can be produced from 5.59 mol of hydrochloric acid is determined from the equation of the reaction.
The equation of the reaction is given below:
Ca²⁺ (aq) + 2 HCl (aq) ---> CaCl₂ (s) + H₂ (g)
From the equation of the reaction, the mole ratio of HCL and calcium chloride is 2 : 1
Therefore, moles of calcium chloride that can be produced will be:
The moles of calcium chloride = 5.59 moles * 1/2
The moles of calcium chloride = 2.795 moles
The mass of calcium chloride produced = moles * molar mass
Molar mass of calcium chloride = 111 g/mol
Mass of calcium chloride produced = 2.795 * 111
Mass of calcium chloride produced = 310.245 g
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<span>Dmitri Mendeleev published first the periodic. He didn't "discover" any elements but predicted where some would be on his table. These included Gallium and Germanium.</span>
The error caused will lower the number of moles when he did not do the second heating.This question is related to the empirical formula.
<h3>What is Empirical formula ?</h3>
A formula giving the proportions of the elements present in a compound but not the actual numbers or arrangement of atoms.
The empirical formula is the simplest ratio of atoms in a given compound.
we know that heating is used to eliminate most of the water molecules which are attached to the compound in the question, it's given that the second heating was not performed by the students.
This means that there are still some water molecules attached to the compound. This will imply that higher mass will be calculated for the compound because the water molecules are also considered.
So now, if we look at the calculation for the number of moles of water in this, we can say that this will be lower than the actual amount.
This is because there are some unaccounted moles of water which are still attached to the compound and these will be accounted in the compound mass rather than the waters. Therefore, the number of moles will be lower.
Hence, The error caused will lower the number of moles when he did not do the second heating.
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